PLEASE HELP WILL MARK BRAINLIEST
1 answer:
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Step-by-step explanation:
∆PQR similar to ∆ JKL
JK/KL= PQ/QR
6/12=3/QR
QR=3×2= 6
therefore, tan(R) = PQ/QR = 3/6=1/2
and, tan(J) = KL/JK =12/6=2
tan(J)=4.tan(R)
option D
<u>Answer: </u>
The vertex of the function is (h,k) = (3 , -1)
<u>Solution: </u>
The vertex form of quadratic equation is generally given as,
Where h,k is the vertex of the parabola.
From question, given that .
we have to find the vertex of the function.
Let us first convert the given quadratic equation to vertex form (eqn 1)
By adding “9” on both sides of equation, we get
By using the identity ,the right hand side of above equation becomes,
Now,the equation is of the vertex form.
By comparing with
we get the values of (h,k)
a = 1; h = 3; k = -1
hence the vertex of the function is (h,k) = (3 , -1)