Answer:
30 atm
Explanation:
Initial Volume, V1 = 3L
Initial Pressure, P1 = 100 atm
Final Volume V2 = 10 L
Final Pressure, P2 = ?
These quantities are related by the Boyle's law equation which is given as;
V1P1 = V2P2
P2 = V1 * P1 / V2
P2 = 3 * 100 / 10
P2 = 30 atm
Answer:
Here's what I get
Explanation:
SbCl₃ reacts with water to form slightly soluble antimony oxychloride.
SbCl₃(aq) +H₂O(ℓ) ⇌ SbOCl(s) + 2HCl(aq)
Your observation is an example of Le Châtelier's Principle in action,
The SbCl₃(aq) in your lab has enough HCl added to push the position of equilibrium to the left and keep the SbOCl in solution.
If a few drops of the SbCl₃(aq) were added to 300 mL of water, the solution would turn cloudy. The HCl would be so dilute that the position of equilibrium would lie to the right, and a cloudy precipitate of antimony oxychloride would form.
M = 4 g = 4/1000 kg = 0.004 kg, θ₂ = 21.0°C, θ₁ = 0°C , c = 0.44kJ/kg°C,
Q = mc(θ₂ - θ₁)
Q = 0.004*0.440*(21 - 0)
Q = 0.03696 kJ
0.03696 kJ<span> of heat is absorbed.</span>
<span>So when the chemist combines Ethane (CH3CH3) and Chlorine (Cl2) with the intention of producing Chloroethane (CH3CH2Cl), the other product that's formed in this reaction is 1,2-dichloroethane (ClCH2CH2Cl) also called as Ethylene dichloride with molecular weight of 98.954 g/mol. This is a colorless oily flammable substance that weighs heaver when vaporized.</span>