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Vlad [161]
3 years ago
8

the pressure in a car tire is 198 kpa at 27°C. After a long drive the pressure is 225 kpa. what is the temperature of the air in

the tire? assume that the volume is Constant.
Chemistry
1 answer:
Grace [21]3 years ago
7 0

Answer:

340.9°k ~ 67.8°C

Explanation:

This is an example of Gay-Lussac's law, which states that the pressure of a given amount of gas held at constant volume is directly proportional to the Kelvin temperature. This means that if the volume increases, so does the temperature, and vice versa.

The equation for this gas law is:

P1/T1 = P2/T2

Known

P1 = 198 kPa

T1 = 27°C + 273.15 = 300°K ← Temp. must be in Kelvins

P2 = 225 kPa

T2 = ?

Solution

Rearrange the equation to isolate T2

Input the known values and solve.

T2 = T1P2/P1

Where:

T2 = 300°K × 225kPa/198kPa = 340.91°K

T2 in °C = 340.91°K − 273.15 = 67.8°C

note: answers were rounded off to one decimal point.

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How much time will it take a car traveling at an average of 75 mph to go a distance of 225 miles​
mojhsa [17]

Time taken = 3 hours

<h3>Further explanation</h3>

Given

speed : 75 mph

distance : 225 miles

Required

time taken

Solution

An equation of constant velocity motion  

\large {\boxed {\bold {d = v \times \: t}}}

d = distance = m  

v = speed = m / s  

t = time = seconds  

Input the value :

t = d : v

t = 225 miles : 75 miles/hour

t = 3 hours

7 0
3 years ago
Instead of 6 M NaOH being added to the solution, 6 M HCl is added. How will this affect the test for the presence of ammonium io
Lera25 [3.4K]

Answer:

Ammonia gas(an alkaline gas with characteristics of choking or irritating smell) is not liberated when 6mole of HCl is added to the solution instead of 6mole of NaOH, to test for the presence of ammonium ion in the solution

Explanation:

As expected, when testing for ammonium ion in a solution (precisely ammonium salt solution), Sodium Hydroxide (NaOH) is required as the test reagent.

When NaOH is added to the solution, A gas with characteristics of choking or irritating smell is liberated.

This gas turn red litmus paper blue.

This liberated gas is an alkaline gas, which is confirmed as an ammonia gas(NH3).

If HCl is added instead of NaOH, the ammonia gas will not be liberated, which indicates that the test reagent used is wrong.

3 0
3 years ago
Heat transmits readily through this
Oksi-84 [34.3K]
Can you be more specific?

...Diamond is the best conductor of heat, but heat also transmits readily through many other substances. Do you have multiple choice?
8 0
3 years ago
HELP FAST 100 PTSCalculate the amount of heat needed to convert 100.0 g of liquid water at 25 °C to water at 100 °C.
Alex Ar [27]

Answer:

31,380 Joules

Explanation:

Given Data:

Mass = m = 100 g

Temperature 1 = = 25 °C

Temperature 2 = = 100 °C

Specific Heat Constant = c = 4.184

Change in Temp. = ΔT = 100 - 25 = 75 °C

Required:

Heat = Q = ?

Formula:

Q = mcΔT

Solution:

Q = (100)(4.184)(75)

Q = 31, 380 Joules

Hope this helped!

~AH1807

4 0
3 years ago
Read 2 more answers
Give the formula for an ionic compound formed from each pair of ions
Vera_Pavlovna [14]

Please, find the complete question in the picture attached.

Answer:

1. Na₂O

2. AlF₃

3. MgO

4. Ca₃P₂

Explanation:

1. Na⁺ and O²⁻

An ionic compound will be formed when two ions of opposite charge attract each other.

The positive ion is called cation and the negative ion is called anion.

Thus, every ionic compound has a cation and an anion electrostatically bonded.

The ions must combine in a proportion that genders a neutral compound: so you must have as many cations as negative charge has one anion and as many anions as positive charge has one cation.

This is, if the cation has charge +x, there will be x anions, and if the anion has charge -y, there will be y cations.

Simbolically:

Cation:A^{+x}\\ \\ Anion:B^{-y}\\ \\ Compound:A_yB_x

As you see, the subscripts for each element in the chemical formula are obtained by the exchage of the charges of the ions.

Then, for Na⁺ and O²⁻, the subscript for Na will be 2 and the subscript for O will be 1; and the formula of the ionic compound formed by this pair ot ions is:

  • Na₂O

2. Al³⁺ and F⁻

  • The subscript of Al will be 1 (because the F ion has charge 1-, and the subscript of F will be 3 (because the Al ion has charge +3).

Thus the ionic compound formed by this pair of ions is:

  • AlF₃

3. Mg²⁺ and S²⁻

  • The charge 2+ from Mg atom wil become the subscript 2 of S atom, and the charge 2- will become the subscript 2 of Mg atom:

That results in the formula: Mg₂S₂

Except for some special compounds, the chemical formula is simplified, dividing by the least common denominator. In this case, that means that the two 2 subscripts are simplified to 1, and the final chemical formula for the ionic compound formed by this pair of ions is:

  • MgO

4. Ca²⁺ and P³⁻

  • The charge 2+ from Ca will become subscript 2 for P and the charge 3- whill become subscript 3 for Ca.

Hence, the ionic compound formed by these two ions is:

  • Ca₃P₂

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