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Vlad [161]
3 years ago
8

the pressure in a car tire is 198 kpa at 27°C. After a long drive the pressure is 225 kpa. what is the temperature of the air in

the tire? assume that the volume is Constant.
Chemistry
1 answer:
Grace [21]3 years ago
7 0

Answer:

340.9°k ~ 67.8°C

Explanation:

This is an example of Gay-Lussac's law, which states that the pressure of a given amount of gas held at constant volume is directly proportional to the Kelvin temperature. This means that if the volume increases, so does the temperature, and vice versa.

The equation for this gas law is:

P1/T1 = P2/T2

Known

P1 = 198 kPa

T1 = 27°C + 273.15 = 300°K ← Temp. must be in Kelvins

P2 = 225 kPa

T2 = ?

Solution

Rearrange the equation to isolate T2

Input the known values and solve.

T2 = T1P2/P1

Where:

T2 = 300°K × 225kPa/198kPa = 340.91°K

T2 in °C = 340.91°K − 273.15 = 67.8°C

note: answers were rounded off to one decimal point.

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Explanation:

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As the given reaction is as follows.

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(a)  When increase the temperature of the reactants or system then equilibrium will shift in forward direction where there is less temperature. It is possible for an endothermic reaction.

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Hence, formation of H_{2}S will decrease with decrease in volume.

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How many valence electrons do alkali metals have?
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What mass of HBO2 is produced from the<br> combustion of 139.5 g of B2H6?<br> Answer in units of g.
aliina [53]

Answer:

m_{HBO_2}=441.8gHBO_2

Explanation:

Hello there!

In this case, since the combustion of B2H6 is:

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Thus, since there is 1:2 mole ratio between the reactant and product, the produced grams of the latter is:

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