Answer:
340.9°k ~ 67.8°C
Explanation:
This is an example of Gay-Lussac's law, which states that the pressure of a given amount of gas held at constant volume is directly proportional to the Kelvin temperature. This means that if the volume increases, so does the temperature, and vice versa.
The equation for this gas law is:
P1/T1 = P2/T2
Known
P1 = 198 kPa
T1 = 27°C + 273.15 = 300°K ← Temp. must be in Kelvins
P2 = 225 kPa
T2 = ?
Solution
Rearrange the equation to isolate T2
Input the known values and solve.
T2 = T1P2/P1
Where:
T2 = 300°K × 225kPa/198kPa = 340.91°K
T2 in °C = 340.91°K − 273.15 = 67.8°C
note: answers were rounded off to one decimal point.
