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Vlad [161]
3 years ago
8

the pressure in a car tire is 198 kpa at 27°C. After a long drive the pressure is 225 kpa. what is the temperature of the air in

the tire? assume that the volume is Constant.
Chemistry
1 answer:
Grace [21]3 years ago
7 0

Answer:

340.9°k ~ 67.8°C

Explanation:

This is an example of Gay-Lussac's law, which states that the pressure of a given amount of gas held at constant volume is directly proportional to the Kelvin temperature. This means that if the volume increases, so does the temperature, and vice versa.

The equation for this gas law is:

P1/T1 = P2/T2

Known

P1 = 198 kPa

T1 = 27°C + 273.15 = 300°K ← Temp. must be in Kelvins

P2 = 225 kPa

T2 = ?

Solution

Rearrange the equation to isolate T2

Input the known values and solve.

T2 = T1P2/P1

Where:

T2 = 300°K × 225kPa/198kPa = 340.91°K

T2 in °C = 340.91°K − 273.15 = 67.8°C

note: answers were rounded off to one decimal point.

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Consider two different ions. The anion has a valence of -2. The cation has a valence of +2. The two ions are separated by a dist
strojnjashka [21]

Answer:

Force of attraction = 35.96 \times 10^{27}N

Explanation:

Given: charge on anion = -2

Charge on cation = +2

Distance = 1 nm = 10^{-9} m

To calculate: Force of attraction.

Solution: The force of attraction is calculated by using equation,

F = \dfrac{k \times q_1 q_2}{ \r^2} ---(1)

where, q represents the charge and the subscripts 1 and 2 represents cation and anion.

k = 8.99 \times 10^9 \ Nm^{2}C^{-2}

F = force of attraction

r = distance between ions.

Substituting all the values in the equation (1) the equation becomes

F = \dfrac{8.99 \times 10^9 \times 2 \times 2}{ \left ( 10^-9 \right )^2 }

Force of attraction = 35.96 \times 10^{27}N

6 0
3 years ago
Oxygen is a __________ and nitrogen is a __________. metalloid, metalloid nonmetal, metal nonmetal, nonmetal nonmetal, metalloid
Anna35 [415]

Answer:

"nonmetal, nonmetal"

Explanation:

Oxygen is a non metal and Nitrogen is a non metal. It is 8th element of the periodic table. It is located in period 2 and group 16.

Nitrogen lies at the group 15 of the periodic table. Its atomic no is 7. Its valency is 2.

Hence, the correct option is (c) "nonmetal, nonmetal".

4 0
3 years ago
Why are fixed resistors’ values indicated by color bands rather than printing the numeric value on their exterior?
gladu [14]
Because there are so many different values of numbers, it would be impractical to use 1Ω, 2Ω, 3Ω... etc... Using colored bands helps make reading it a little easier to the trained eye. There are hundreds of thousands, if not tens of millions of different resistors would need to exist to cover every value. So you just use something called "preferred values" with their resistance values posted on them instead.
6 0
3 years ago
1. a) Binary ionic and binary molecular compounds have what two things that are similar in their composition? (b) What is one wa
kherson [118]
Binary compounds consist of only two distinct elements, regardless of whether the compound is ionic or molecular. Water is a binary compound, as are calcium chloride, ammonia, and potassium iodide. 

<span>An ionic binary compound consists of cations of one element and anions of another. KI is an ionic binary compound, composed of K cations and I anions. </span>

<span>A molecular binary compound does not consist of discrete ions, but of molecules. H2O is molecular, as is NH3.</span>
7 0
3 years ago
n a gas-phase equilibrium mixture of SbCl5, SbCl3, and Cl2 at 500 K, pSbCl5 = 0.17 bar and pSbCl3 = 0.22 bar. Calculate the equi
Lorico [155]

Answer:

2.7 × 10⁻⁴ bar

Explanation:

Let's consider the following reaction at equilibrium.

SbCl₅(g) ⇄ SbCl₃(g) + Cl₂(g)

The pressure equilibrium constant (Kp) is 3.5 × 10⁻⁴. We can use these data and the partial pressures at equilibrium of SbCl₅ and SbCl₃, to find the partial pressure at equilibrium of Cl₂.

Kp = pSbCl₃ × pCl₂ / pSbCl₅

pCl₂ = Kp × pSbCl₅ / pSbCl₃

pCl₂ = 3.5 × 10⁻⁴ × 0.17 / 0.22

pCl₂ = 2.7 × 10⁻⁴ bar

7 0
3 years ago
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