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4 years ago

14

a scale drawn on the map shows that 1 inch represents 16 miles. if two cities are 3.25 inches apart on the map, what is the dist

ance between them in real life?

1 answer:

quester [9]4 years ago

7 0

Multiply 3.25 by 16 = 52 miles

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A shopper paid $2.52 for 4.5 pounds of potatoes, $7.75 for 2.5 pounds of broccoli, and $2.45 for 2.5 pounds of pears. what is th

kobusy [5.1K]

Answer:

a) UNIT PRICE of potatoes is $0.56

b) UNIT PRICE of broccoli is $3.1

c) UNIT PRICE of broccoli is $0.98

Step-by-step explanation:

UNIT PRICE is defined as the price of 1 unit.

$\textrm{Unit Price} = \frac{\textrm{Total cost on n products}}{\textrm{n}}$

Now, here in the given question:

1. Cost of 4.5 pounds of potatoes is $2.52

So, the unit price of potatoes $= \frac{\textrm{2.52}}{\textrm{4.5}} = 0.56$

⇒ 1 pound of potatoes cost $0.56

Hence,UNIT PRICE of potatoes is $0.56

2 Cost of 2.5 pounds of broccoli is $7.75.

So, the cost of 1 pound of broccoli $= \frac{\textrm{7.75}}{\textrm{2.5}} = 3.1$

⇒ 1 pound of broccoli cost $3.1

Hence,UNIT PRICE of broccoli is $3.1

3. Cost of 2.5 pounds of pears is $2.45.

So, the cost of 1 pound of pears $= \frac{\textrm{2.45}}{\textrm{2.5}} = 0.98$

⇒ 1 pound of pears cost $0.98

Hence,UNIT PRICE of broccoli is $0.98

5 0

3 years ago

Read 2 more answers

What is the value of y?<br><br> A. <br> 16<br><br> B. <br> 48<br><br> C. <br> 64<br><br> D.<br> 132

lorasvet [3.4K]

Answer:

3x+3x+7x+20+7x+20=360

20x=360-20

20x=320

x=16

therefore x=16 so,

7x+20+y=180

but x=16

7(16)+20+y=180

y=180-132

y=48

6 0

2 years ago

Write the standard form of the line that passes through (-1,-3) and (2,1).

kobusy [5.1K]

Answer:

Step-by-step explanation:

$\mathrm{Line\:passing\:through\:}\left(-1,\:-3\right)\mathrm{,\:}\left(2,\:1\right)\\\\\mathrm{Find\:the\:line\:}\\\mathbf{y=mx+b}\mathrm{\:passing\:through\:}\left(-1,\:-3\right)\mathrm{,\:}\left(2,\:1\right)\\\\\mathrm{Compute\:the\:slope\:}\left(-1,\:-3\right),\:\left(2,\:1\right):\quad \\m=\frac{4}{3}\\\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}\\\\\left(x_1,\:y_1\right)=\left(-1,\:-3\right),\:\left(x_2,\:y_2\right)\\\left\\$

$\\m=\frac{1-\left(-3\right)}{2-\left(-1\right)}\\\\Refine\\\\m=\frac{4}{3}\\\\\mathrm{Compute\:the\:}y\mathrm{\:intercept}:\quad b=-\frac{5}{3}\\\\y=\frac{4}{3}x-\frac{5}{3}\\$

Convert equation to standard form

$y - \frac{4}{3} x + \frac{5}{3} = 0\\\\Multiply \:through\: by\: 3;\\\\3\times (y - \frac{4}{3} x + \frac{5}{3} )=0\\\\3y -4x+5 = 0\\Arrange\:n\:form\:of \:;\\Ax +By = C\\\\-4x +3y =-5$

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4 years ago

The points A,B and C lie on a straight line

aev [14]

I think 0 but if I am wrong I'm sorry

Step-by-step explanation:

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3 years ago

What is the standard form of 3+5x-4x^2<br>and what is the standard form of 8x+x+5+x^3

harina [27]

Answer:

1. -4x^2 + 5x + 3

2. x^3 + 9x + 5

Step-by-step explanation:

hope this helps

4 0

3 years ago