There are 0.15 ml of the water contains 150 mg of Pb .
Calculation ,
Formula used :
density = mass / volume ( i )
Given mass of the Pb in milligram ( mg ) = 150 mg
Given mass of the Pb in gram ( g ) = 150 × 
= 0.15 gram
Given density = 1.0 g/ml
We have to find volume of water in milliliter ( ml ) .
Putting the value of mass of the Pb , lead and density in equation ( i ) we get the volume of water in milliliter ( ml ) .
density = mass / volume
1.0 g/ml = 0.15 gram / volume
volume = 0.15 gram / 1.0 g/ml = 0.15 ml
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Answer:
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Explanation:
Since the compound has 1.38 time that of oxygen gas at the same conditions of temperature and pressure, we have the relationship:
MW/MWoxygen = 1.38
MW = 44.16
Since there is water formed during the reaction, the formula of the compound must be:
XaHb
where a and b are the coefficients of each element.
If the compound reactions with oxygen forming water and an oxide of the element X, the combustion reaction must be:
XaHb + ((2a + (b/2))/2) O2 = a (XO2) + (b/2)(H2O)
Using dimensional analysis:
10 (1/44.16) (b/2 / 1) (18) = 16.3
Solving for b:
b = 8
The compound now is XaH8. Most probably, the compound is C3H8 since it has a molecular formula of 44 and it reacts with O2 to form water and CO2.
