Assuming that the initial pH is pHi.
The initial concentration of [OH-] is
[OH]- = 10^(14 - pHi)
Since half of the Na2HPO4 is neutralized, the concentration of [OH-] will be reduced to half. The new pH will be
[OH-]/2 = 10^(14 - pHi)/2 = 10^(14 - pH)
14 - pHi - log 2 = 14 - pH
In terms of pHi,
pH = pHi + log 2
Hey there!:
Molar mass CO2 = 44.01 g/mol
44.01 g CO2 ------------------- 6.02*10²² molecules CO2
88 g CO2 ------------------------ y
y = 88 * ( 6.02*10²² ) / 44.01
y = 5.29*10²⁵ / 44.01
y = 1.2 * 10²⁴ molecules of CO2
Answer A
Hope that helps!
Meteorites, I think it’s an asteroid when in space and a meteorite once it lands
