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3 years ago

if you increased the mass of planet by 2 what would happen to the gravitational force of the planet

Chemistry

1 answer:

Karo-lina-s [1.5K]3 years ago

4 0

Answer:

One way to find out is to change “passive mass” - the dirt and rocks of Earth - and convert it into “active mass” - add energy “E” to it. If we increase the energy “E” we will increase its mass. The key is, how do you turn “passive mass” into “active mass” by adding energy “E” to the “passive mass”? After all, isn’t “passive mass” of the Earth just the dirt and rocks that make up the planet?

Explanation:

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<u>Answer: </u>The molecular weight of the dibasic acid is 89.6 g/mol

<u>Explanation:</u>

Normality is defined as the amount of solute expressed in the number of gram equivalents present per liter of solution. The units of normality are eq/L. The formula used to calculate normality:

$\text{Normality}=\frac{\text{Given mass of solute}\times 1000}{\text{Equivalent mass of solute}\times \text{Volume of solution (mL)}}$ ....(1)

We are given:

Normality of solution = $\frac{1}{20}=0.05N$

Given mass of solute = 0.56 g

Volume of solution = 250 mL

Putting values in equation 1, we get:

$0.05=\frac{0.56\times 1000}{\text{Equivalent mass of solute}\times 250}\\\\\text{Equivalent mass of solute}=\frac{0.56\times 1000}{0.05\times 250}=44.8g/eq$

Equivalent weight of an acid is calculated by using the equation:

$\text{Equivalent weight}=\frac{\text{Molar mass}}{\text{Basicity}}$ .....(2)

Equivalent weight of acid = 44.8 g/eq

Basicity of an acid = 2 eq/mol

Putting values in equation 2, we get:

$44.8g/eq=\frac{\text{Molar mass}}{2eq/mol}\\\\\text{Molar mass}=(44.8g/eq\times 2eq/mol)=89.6g/mol$

Hence, the molecular weight of the dibasic acid is 89.6 g/mol

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Given what we know, we can confirm that option A is correct in that Stronger IMFs lead to stronger adhesion, producing rounder drops with a smaller diameter.

IMF is the acronym used to describe intermolecular forces. These forces include all of the forces that bind molecules together, of which water has plenty. This bonding force creates a high adhesion and thus gives water its surface tension which makes it stay together in the shape of a drop.

Therefore, we can confirm that stronger IMFs lead to stronger adhesion, producing rounder drops with a smaller diameter, and therefore that option A is correct.

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if you increased the mass of planet by 2 what would happen to the gravitational force of the planet ​

if you increased the mass of planet by 2 what would happen to the gravitational force of the planet