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Snezhnost [94]
4 years ago
14

A thin spherical shell of metal has a radius of 0.25 meter and carries a charge 0.2 mC. Calculate the electric intensity at a po

int (i) inside the shell, (ii) just outside the shell (iii) 3 m from the center of the shell. (Ans: zero ; 2.88 x 104 N/C ; 200 N/C) 4. Two large, thin metal
Physics
1 answer:
Minchanka [31]4 years ago
4 0

Answern:no it’s all wrong it’s 3.00 and the third is .22 and the thirds is .15

Explanation:

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What demonstrates the flow of energy and materials through
Tcecarenko [31]
A. Food chain

A food web also shows the flow of energy and materials through an ecosystem but in a complex web, not a single chain. A biogeochemical cycle does not deal with the flow of energy/materials through an ecosystem at all.
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1 year ago
How would you go about separating the components of a mixture of sand, gravel, salt and iron filings
larisa86 [58]

Pour the entire components into water.

First the iron filings can be separated using a magnet as iron is a magnetic element.

By pouring the mixture into water, it allows the salt to dissolve in the water, while the sand will not.

Next we can run this solution through a filtration device to separate the sand from the water.

Now all that's left is to let the water evaporate so that the salt will be exposed that dissolved into the water.

4 0
3 years ago
I NEED HELP!!! PLS HELP ME MARK U BRAINLIEST!!
FinnZ [79.3K]

Answer:

The answer is X

Explanation:

Cause the highest points will most likely have the most potential energy

8 0
3 years ago
What is the direction of the normal contact force of the road on the wheels?
Gekata [30.6K]

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The direction of the contact forces acting on a body is not necessarily perpendicular to the contact surface. The resolution of contact forces in two components i.e. perpendicular to contact surface and along surface. Perpendicular component is normal force and parallel component is friction.

Explanation:

3 0
2 years ago
A 70.0 kg astronaut is training for accelerations that he will experience upon reentry. He is placed in a centrifuge (r = 15.0 m
Levart [38]

Answer:

1.3823 rad/s

20.7345 m/s

28.66129935 m/s²

a=2.92164g

2006.29095 N radially outward

Explanation:

r = Radius = 15 m

m = Mass of person = 70 kg

g = Acceleration due to gravity = 9.81 m/s²

Angular velocity is given by

\omega=13.2\times \dfrac{2\pi}{60}\\\Rightarrow \omega=1.3823\ rad/s

Angular velocity is 1.3823 rad/s

Linear velocity is given by

v=r\omega\\\Rightarrow v=15\times 1.3823\\\Rightarrow v=20.7345\ m/s

The linear velocity is 20.7345 m/s

Centripetal acceleration is given by

a_c=r\omega^2\\\Rightarrow a_c=15\times 1.3823^2\\\Rightarrow a_c=28.66129935\ m/s^2

The centripetal acceleration is 28.66129935 m/s²

Acceleration in terms of g

\dfrac{a}{g}=\dfrac{28.66129935}{9.81}\\\Rightarrow a=2.92164g

a=2.92164g

Centripetal force is given by

F_c=ma_c\\\Rightarrow F_c=70\times 28.66129935\\\Rightarrow F_c=2006.29095\ N

The centripetal force is 2006.29095 N radially outward

The torque will be experienced when the centrifuge is speeding up of slowing down i.e., when it is accelerating and decelerating.

3 0
4 years ago
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