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4 years ago

Name the 9 types of energy

Physics

1 answer:

Ugo [173]4 years ago

6 0

Hello There!

-Energy Is The Ability To Do Work-

Energy comes into different forms but they can all be placed in two different categories. These categories are "potential" which means stored energy and energy of position and "kinetic" which is the energy of motion.

POTENTIAL ENERGY Stored energy and the energy of position

CHEMICAL ENERGY Energy in the bonds of atoms and molecules

MECHANICAL ENERGY Energy stored in objects by tension

NUCLEAR ENERGY Energy stored in the nucleus of an atom

GRAVITATIONAL Energy that is stored in an object's height

ELECTRICAL ENERGY Delivered by tiny charged particles called electrons

KINETIC ENERY The energy of motion

THERMAL ENERGY The vibration and movement of atoms and molecules in substances.

RADIANT ENERGY Electromagnetic energy that travels in waves

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The water level in a tank is 20 m above the ground. a hose is connected to the bottom of the tank, and the nozzle at the end of

Damm [24]

Answer:

P_(pump) = 98,000 Pa

Explanation:

We are given;

h2 = 30m

h1 = 20m

Density; ρ = 1000 kg/m³

First of all, we know that the sum of the pressures in the tank and the pump is equal to that of the Nozzle,

Thus, it can be expressed as;

P_(tank)+ P_(pump) = P_(nozzle)

Now, the pressure would be given by;

P = ρgh

So,

ρgh_1 + P_(pump) = ρgh_2

Thus,

P_(pump) = ρg(h_2 - h_1)

Plugging in the relevant values to obtain;

P_(pump) = 1000•9.8(30 - 20)

P_(pump) = 98,000 Pa

5 0

3 years ago

Three charges are located at a different position in a plane: q1= 10μC at →r1=(5,6)cm q2=−27μC at →r2=(−6,10)cm and q3=−12μC at

sasho [114]

Answer:

E = (2.29 i ^ - 0.917 j ^) 10⁶ N / C

E_{total} = 2,467 10⁶ N / A θ = -21.8

Explanation:

For this exercise we will use that the electric field is a vector quantity, so the total field is

E_total = E₁₃ + E₂₃

bold font vectors . We can work with the components of the electric field in each axis

X- axis

E_ total x = E₁₃ₓ + E_{23x}

y-axis

E_{total y} = E_{13y} + E_{23y}

the expression for the electric field is

E = k q / r²

where r is the distance between the charge and the positive test charge

in this exercise

Let's find the field created by charge 1

q₁ = 10 μC = 10 10⁻⁶ C

x₁ = 5 cm = 0.05 m

x₃ = 21 cm = 0.21 m

E_{13x} = 9 10⁹ 10 10⁻⁶ / (0.21 -0.05)²

E_{13x} = 3.516 10⁶ N / C

y₁ = 6 cm = 0.06 cm

y₃ = -12 cm = -0.12 m

E_{13y} = 9 10⁹ 10 10⁻⁶ / (-0.12 - 0.06)²

E_{13y} = 2,777 10⁶ N / C

let's find the field produced by charge 2

q₂ = -27 μC = - 27 10⁻⁶ C

x₂ = -6 cm = -0.06 m

x₃ = 0.21 m

E_{23x} = 9 10⁹ 27 10⁻⁶ / (0.21 + 0.06)²

E_{23x} = 1.23 10⁶ N / A

y₂ = 10 cm = 0.10 m

y₃ = -0.12 m

E_{23y} = 9 10⁹ 27 10⁻⁶ / (-0.12 - 0.10)²

E_{23y} = 1.86 10⁶ N / C

Taking the components we can calculate the total electric field, we must use that charge of the same sign repel and attract the opposite sign, remember that the test charge is always considered positive.

E_{total x} = E_{13x} - E_{23x}

E_{total x} = (3.516 - 1.23) 10⁶

E_{total x} = 2.29 10⁶ N / A

E_{total y} = -E_{13y} + E_{23y}

E_{total y} = (-2.777 +1.86) 10⁶ N / A

E_{total y} = -0.917 10⁶ N / A

we can give the result in two ways

E = (2.29 i ^ - 0.917 j ^) 10⁶ N / C

or in the form of modulus and angle, let's use the Pythagorean theorem to find the modulus

E_{total} = √ (E_{total x}^2 + E_{total y}^ 2)

E_{total} = √ (2.29² + 0.917²) 10⁶

E_{total} = 2,467 10⁶ N / A

let's use trigonometry for the angle

tan θ = E_total and / E_totalx

θ = tan⁻¹ E_{total y} / E_{total x}

θ = tan⁻¹ (-0.917 / 2.29)

θ = -21.8

The negative sign indicates that the angle is measured with respect to the x-axis in a clockwise direction.

7 0

4 years ago

Ava visited grand canyon. She was very impressed by the rock formations and decided to sketch them. What type of rock did Ava se

soldier1979 [14.2K]

She saw sedimentary rock

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3 years ago

What disagreement did Sigmund Freud have with both Josef Breuer and Jean Martin Charcot?

GREYUIT [131]

Answer:

The correct answer is 'A'

Explanation:

I guessed and was correct.

4 0

3 years ago

The y-position of a damped oscillator as a function of time is shown in the figure.

MrRissso [65]

The length of time that an oscillator is allowed to oscillate, as well as its damping coefficient.

t= 1.33s
b = 0.0426 s^-1

<h3>What is the period of the oscillator, and what factors influence the amount of damping that it has?</h3>

In most situations, the equation may be expressed numerically as

When we look at the data and see that there are cycles between the timestamps t= 0s and t= 4s, we may conclude that it finishes three cycles once every four seconds. As a result, the length of time that is going to be necessary to finish one cycle of damping will be

t =4/3sec

t= 1.33s

In most situations, the equation for amplitude may be expressed analytically as

A=A_0e^{-bt}

Therefore

3=5e^{-12b}

$0.6=e^{-12b}$

Therefore

-0.511 = -12b lne

$b = 0.0426 s^{-1}$

In conclusion, damping refers to an influence that either operates from inside an oscillatory system or acts on it and has the consequence of reducing or halting the system from oscillating. This impact might occur from either side of the system. In physical systems, damping is produced by processes that cause the energy that is stored in an oscillation to be lost. These processes are called dissipative. The collective name for these processes is "damping agents." The damping coefficient may thus be written as

$b = 0.0426 s^-1$

Learn more about the damping coefficient by reading up on it.

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4 0

2 years ago