Complete Question
The complete question is shown on the first uploaded image
Answer:
The value of 
and 
Explanation:
Considering the diagram,
Taking moment about the pivot , we have
=>
Generally given that the bar is at equilibrium then the upward forces is equal to the down ward force
So
=> 
=>
Answer:
A. Weight
Explanation:
On Earth a gallon of milk has the same mass as a gallon of milk in space, but it has a different weight
1. V = Vo + a*t.
<span>15 = 0 + a*5 a = 3 m/s^2. </span>
<span>2. V = Vo + a*t. </span>
<span>0 = 15 - 5*t, t = 3 s. </span>
<span>3. d1 = Vo*t + 0.5a*t^2. </span>
<span>Vo = 0, t = 5, a = 3 m/s^2, d1 = ?. </span>
<span>d2 = Vo*t. Vo = 15 m/s, t = 15 s, </span>
<span>d2 = ?. </span>
<span>V^2 = Vo^2 + 2a*d3. </span>
<span>V = 0, Vo = 15 m/s, a = -5 m/s^2, d3 = ?. </span>
<span>d1+d2+d3 = Total dist.</span>
Answer:
a) F₁₂₀ = 1.34 pa A , b) F₂₀ = 0.746 pa A
Explanation:
Part. A
. The definition of pressure is
P = F / A
As the air can approach an ideal gas we can use the ideal gas equation
P V = n R T
Let's write this equation for two temperatures
P₁ V = n R T₁
P₂2 V = n R T₂
P₁ / P₂ = T₁ / T₂
point 1 has a pressure of P₁ = pa and a temperature of (20 + 273) K, point 2 is at (120 + 273) K, we calculate the pressure P₂
P₂ = P₁ T₂ / T₁
P₂ = pa 393/293
P₂ = 1.34 pa
We calculate the strength
P₂ = F₁₂₀ / A
F₁₂₀ = 1.34 pa A
Part B
In this case the data is
Point 1 has a temperature of 393K and an atmospheric pressure (P₁ = pa), point 2 has a temperature of 293K, let's calculate its pressure
P₁ / P₂ = T₁ / T₂
P₂ = P₁ T₂ / T₁
P₂ = pa 293/393
P₂ = 0.746 pa
Let's calculate the force (F20), from this point
F₂₀ / A = 0.746 pa
F₂₀ = 0.746 pa A
lake effect snow is the correct answer
