All categories

3 years ago

PLZ ANSWER ASAP!!!!!!!

Mathematics

2 answers:

VashaNatasha [74]3 years ago

8 0

Answer:

u = 3w - 4.5

Step-by-step explanation:

Step 1: -2u + 6w = 9 - Solve for u by isolating the variable u.

Step 2: Subtract 6w both sides

-2u = 9 - 6w

Step 3: Divide by -2 both sides

u = ( 9 - 6w ) / ( -2 )

u = 3w - 4.5

Have a good day!! :)

olchik [2.2K]3 years ago

7 0

Answer:

u=(9-6w)÷-2

Step-by-step explanation:

You might be interested in

The sum of the digits of a certain two-digit number is 7. Reversing its digits increases the number by 9. What is the number? wr

dimaraw [331]

Xy is the number

A) x + y = 7
B) 10y + x = 10x + y + 9
collecting terms of equation B
B) -9x + 9y = 9
multiplying A) by 9
A) 9x + 9y = 63 then adding it to equation B)
B) -9x + 9y = 9
18y = 72
y = 4
x = 3

The number is 34

4 0

3 years ago

What’s another way to write 56

Viktor [21]

Answer:

56.00 OR 5.6* 10^-1

5 0

3 years ago

Read 2 more answers

My homework says rewrite each statement using symbols for example one says

timurjin [86]

Well the question says "rewrite each statement using symbols so I guess it means using symbols...

4 0

3 years ago

Read 2 more answers

.William sold half of his comic book collection and then purchased 10 more . He now has 24 comic books period how many books did

Assoli18 [71]

Answer:

28 books

Step-by-step explanation:

Let x represent the number of books .William owned before anything happens

x/2 + 10 = 24

2(x/2 + 10) = 2(24)

x + 20 = 48

x = 48 - 20

x = 28

8 0

2 years ago

Read 2 more answers

For the differential equations dydx=sqrt(y^2−36) does the existence/uniqueness theorem guarantee that there is a solution to thi

julsineya [31]

Answer:

1. (-4,6) there is no a solution to the equation through this point

2. (2,−6) there is no a solution to the equation through this point

3. (−5,39) there is a solution to the equation through this point

4. (−1,45) there is a solution to the equation through this point

Step-by-step explanation:

Using the existence and uniqueness theorem:

Let:

$F(x,y)=\sqrt{y^2-36} \\\\and\\\\\frac{\partial F}{\partial y} =\frac{y}{\sqrt{y^2-36} }$

Now, let's find the domain of $F(x,y)$ , due to the square root:

$y^2-36 \geq 0\\\\y^2\geq 36\\\\y \geq 6\hspace{12}or\hspace{12}y\leq-6$

So the domain of the function is:

$y \in R\hspace{12}y\geq6\hspace{12}or\hspace{12}y\leq-6$

Now, due to the fraction $\frac{\partial F}{\partial y}$ the denominator must be also different from 0, so:

$y^2-36\neq0\\\\y \neq \pm6$

So, the theorem tells us that for each $y_0\in R:\hspace{12}y_0>6\hspace{12}or\hspace{12}y_0$ there exists a unique solution defined in an open interval around $x_0$ .

1. (-4,6) there is no a solution to the equation through this point because $y_0=6$

2. (2,−6) there is no a solution to the equation through this point because

$y_0=-6$

3. (−5,39) there is a solution to the equation through this point because

$y_0>6$

4. (−1,45) there is a solution to the equation through this point because

$y_0>6$

6 0

3 years ago