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FrozenT [24]
3 years ago
13

Please help me it will be very much appreciated

Mathematics
1 answer:
AveGali [126]3 years ago
8 0

Answer:

ΔABC ≅ ΔFED

Explanation:

Look at the alignment and position of the letters.

A = F

B = E

C = D

Properly align the letters in order to their corresponding position.

ΔA ≅ ΔF

ΔAB ≅ ΔFE

ΔABC ≅ ΔFED

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Find the equation of the line containing the points (0,3) and (1,8)
Tema [17]

Answer:

y = 5x + 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

To calculate m use the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 3) and (x₂, y₂ ) = (1, 8)

m = \frac{8-3}{1-0} = 5

Note the line crosses the y- axis at (0, 3) ⇒ c = 3

y = 5x + 3 ← equation in slope- intercept form

5 0
3 years ago
Please help me with this homework question. No silly answers please and no bots! I will mark brainliest to whoever gets all them
MatroZZZ [7]

Answer:

The formula for the area of the triangle is:

\displaystyle A=24x^2

When <em>x</em> = 3, the area is 216 square centimeters.

When <em>x </em>= 2.4, the area is 138.24 square centimeters.

And when <em>x</em> = 5, the hypotenuse of the triangle is 50 centimeters.

Step-by-step explanation:

We are given a right triangle with a height of 8<em>x</em> and a base of 6<em>x</em>.

The area of a triangle is given by the formula:

\displaystyle A=\frac{1}{2}bh

So, by substitution:

\displaystyle A=\frac{1}{2}(8x)(6x)=24x^2

When <em>x </em>= 3, the area will be:

\displaystyle A(3)=24(3)^2=216\text{ cm}^2

And when <em>x</em> = 2.4, the area will be:

A(2.4)=24(2.4)^2=138.24\text{ cm}^2

When <em>x </em>= 5, the height will be 8(5) = 40 cm and the base will be 6(5) = 30 cm.

By the Pythagorean Theorem:

a^2+b^2=c^2

So:

(40)^2+(30)^2=c^2

The hypotenuse will be:

c=\sqrt{1600+900}=\sqrt{2500}=50\text{ cm}

3 0
3 years ago
Jdjdudhddbbddbdbdbxb
zzz [600]

Answer:

1.6y+y-4/15y+7/6y=21/3

We move all terms to the left:

1.6y+y-4/15y+7/6y-(21/3)=0

Domain of the equation: 15y!=0

y!=0/15

y!=0

y∈R

Domain of the equation: 6y!=0

y!=0/6

y!=0

y∈R

We add all the numbers together, and all the variables

1.6y+y-4/15y+7/6y-7=0

We add all the numbers together, and all the variables

2.6y-4/15y+7/6y-7=0

We calculate fractions

2.6y+(-24y)/90y^2+105y/90y^2-7=0

We multiply all the terms by the denominator

(2.6y)*90y^2+(-24y)+105y-7*90y^2=0

We add all the numbers together, and all the variables

(+2.6y)*90y^2+(-24y)+105y-7*90y^2=0

We add all the numbers together, and all the variables

105y+(+2.6y)*90y^2+(-24y)-7*90y^2=0

Wy multiply elements

-630y^2+105y+(+2.6y)*90y^2+(-24y)=0

We get rid of parentheses

-630y^2+105y+(+2.6y)*90y^2-24y=0

We add all the numbers together, and all the variables

-630y^2+81y+(+2.6y)*90y^2=0

Step-by-step explanation:

5 0
3 years ago
The cubic equation x³ + ax² + bx - 36 = 0 has a repeated positive integer root.
raketka [301]

Answer:

Step-by-step explanation:

hello !  here is an solution

3 0
2 years ago
How do you solve this inequality? <br><br> y &gt; 14/3
tangare [24]

Answer:

Step-by-step explanation:

it would be D i got it right

i hope this help

4 0
2 years ago
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