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DochEvi [55]
4 years ago
12

Find the centripetal force needed by a 1275 kg car to make a turn of radius 40.0 m at a speed of 25.0 km/h

Physics
2 answers:
dimulka [17.4K]4 years ago
6 0

Answer:

1540

Explanation:

natima [27]4 years ago
4 0
<span>v = 25.0 km/</span><span>h = 25*5/18 m/s = 6.94 m/s

</span><span>centripetal force = mv²/r = 1275*6.94²/40 = 1537.18 N </span>

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Explanation:

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W=\left(\frac{1}{\sqrt{1-\frac{v_f^2}{c^2}}}-\frac{1}{\sqrt{1-\frac{v_i^2}{c^2}}}\right)E_r\\\Rightarrow W=\left(\frac{1}{\sqrt{1-0.9^2}}-\frac{1}{\sqrt{1-0.5^2}}\right)0.511\\\Rightarrow W=0.582\ MeV

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