Find the centripetal force needed by a 1275 kg car to make a turn of radius 40.0 m at a speed of 25.0 km/h
2 answers:
<span>v = 25.0 km/</span><span>h = 25*5/18 m/s = 6.94 m/s </span><span>centripetal force = mv²/r = 1275*6.94²/40 = 1537.18 N </span>
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Answer:
0.582 MeV
2.45 MeV
Explanation:
=Electron rest energy
(a) 0.500c to 0.900c
Energy required is 0.582 MeV
(b) 0.900c to 0.990c
Energy required is 2.45 MeV
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Answer:
Convection
Explanation:
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