Scientists bred the moths and figured out that the light-colored form of the peppered moth has different genes from the dark form. The black color of the dark form was due to a mutation in the DNA of the light-colored form.
Answer:
W = 234 J
Explanation:
Initial volume of air is given as
![V_1 = 0.25 m^3](https://tex.z-dn.net/?f=V_1%20%3D%200.25%20m%5E3)
![P_1 = 110 kPa](https://tex.z-dn.net/?f=P_1%20%3D%20110%20kPa)
finally it is expanded isothermally to new pressure of 101.3 kPa
![P_2 = 101.3 kPa](https://tex.z-dn.net/?f=P_2%20%3D%20101.3%20kPa)
now by isothermal expansion we know
![P_1V_1 = P_2V_2](https://tex.z-dn.net/?f=P_1V_1%20%3D%20P_2V_2)
![(110 kPa)(0.25) = (101.3)V_2](https://tex.z-dn.net/?f=%28110%20kPa%29%280.25%29%20%3D%20%28101.3%29V_2)
![V_2 = 0.27 m^3](https://tex.z-dn.net/?f=V_2%20%3D%200.27%20m%5E3)
So work done in above process is given as
![W_1 = P_1V_1ln(\frac{P_1}{P_2})](https://tex.z-dn.net/?f=W_1%20%3D%20P_1V_1ln%28%5Cfrac%7BP_1%7D%7BP_2%7D%29)
![W_1 = (110\times 10^3)(0.25) ln(\frac{110}{101.3})](https://tex.z-dn.net/?f=W_1%20%3D%20%28110%5Ctimes%2010%5E3%29%280.25%29%20ln%28%5Cfrac%7B110%7D%7B101.3%7D%29)
![W_1 = 2.26 \times 10^3 J](https://tex.z-dn.net/?f=W_1%20%3D%202.26%20%5Ctimes%2010%5E3%20J)
Now it is cooled to initial volume at constant pressure
so here in this case work done is given as
![W_2 = P(V_2 - V_1)](https://tex.z-dn.net/?f=W_2%20%3D%20P%28V_2%20-%20V_1%29)
![W_2 = (101.3 \times 10^3)(0.25 - 0.27)](https://tex.z-dn.net/?f=W_2%20%3D%20%28101.3%20%5Ctimes%2010%5E3%29%280.25%20-%200.27%29)
![W_2 = -2026 J](https://tex.z-dn.net/?f=W_2%20%3D%20-2026%20J)
Now total work done is given as
![W = W_1 + W_2](https://tex.z-dn.net/?f=W%20%3D%20W_1%20%2B%20W_2)
![W = 2260 - 2026 = 234 J](https://tex.z-dn.net/?f=W%20%3D%202260%20-%202026%20%3D%20234%20J)
The relationship between resistance R and resistivity
![\rho](https://tex.z-dn.net/?f=%5Crho)
is
![R= \frac{\rho L}{A}](https://tex.z-dn.net/?f=R%3D%20%5Cfrac%7B%5Crho%20L%7D%7BA%7D%20)
(1)
where L is the length of the wire and A is the cross-sectional area.
In our problem, the radius of the wire is half the diameter: r=1 mm=0.001 m, so the cross-sectional area is
![A=\pi r^2 = \pi (0.001 m)^2=3.14 \cdot 10^{-6} m^2](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E2%20%3D%20%5Cpi%20%280.001%20m%29%5E2%3D3.14%20%5Ccdot%2010%5E%7B-6%7D%20m%5E2)
The length of the wire is L=20 m and the resistance is
![R=0.25 \Omega](https://tex.z-dn.net/?f=R%3D0.25%20%5COmega)
.
By re-arranging equation (1), we can find the resistivity of the wire:
V=f*lambda .. so make lambda the subject.. Lambda is equal to V/ F ... the answer is 6.66*10^3. I converted km to meters
Its B , Lizabeth thinks Miss Lottie and her marigolds are strange, and her frustration with her own life drives Lizabeth to destroy the women's flowers.