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weeeeeb [17]
3 years ago
11

In a laboratory experiment, a diffraction grating produces an interference pattern on a screen. If the number of slits in the gr

ating is increased, with everything else (including the slit spacing) the same, thenA.The fringes stay the same brightness and get closer together.B.The fringes stay the same brightness and get farther apart.C.The fringes stay in the same positions but get brighter and narrower.D.The fringes stay in the same positions but get dimmer and wider.E.The fringes get brighter, narrower, and closer together.
Physics
1 answer:
8_murik_8 [283]3 years ago
4 0

Answer:

C

Explanation:

Diffraction grating is an optics tool used when there is a need to separate light of different wavelengths using a high resolution. This tool is used in:

  • Optical pulse compressing devices
  • Spectrometers
  • Lasers
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3 years ago
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Mains electricity is an ac supply. Explain the difference between direct and alternating potential difference.
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5 0
3 years ago
What happened to the balloon when it was placed on the bottle with the baking soda and vinegar and why.
user100 [1]

Answer:

The ballon would be inflated. The reason is that the sodium bicarbonate in baking soda reacts with acetic acid in vinegar to produce gas.

Explanation:

The main component of baking soda is sodium bicarbonate, {\rm Na_{2}CO_{3}}.

Vinegar is mostly a solution of acetic acid {\rm CH_{3}COOH} in water.

Acids such as acetic acid react with carbonate salts. One of the products of such reactions is carbon dioxide {\rm CO_{2}}, a gas.

In this question, when the acetic acid in vinegar reacts with sodium bicarbonate in the baking soda, the following reaction would occur:

\begin{aligned}& {\rm Na_{2}CO_{3}}\, (aq) + 2\, {\rm CH_{3}COOH}\, (aq) \\ &\to 2\, {\rm CH_{3}COONa}\, (aq) + {\rm CO_{2}}\, (g)\end{aligned}.

The {\rm CO_{2}} produced would then inflate the ballon placed on the opening of the bottle.

5 0
2 years ago
A 70.0 kg ice hockey goalie, originally at rest, has a 0.110 kg hockey puck slapped at him at a velocity of 31.5 m/s. Suppose th
NISA [10]

Answer

given,

mass of the goalie(m₁) = 70 kg

mass of the puck (m₂)= 0.11 kg

velocity of the puck = 31.5 m/s

elastic collision

v_1=\dfrac{m_2-m_1}{m_1+m_2}v_1+\dfrac{2m_2}{m_1+m_2}v_2

v_{pf}=\dfrac{0.11-70}{0.11+70}31.5+\dfrac{2m_2}{m_1+m_2}\times (0)

v_{pf}=-31.4\ m/s

v'_2 = \dfrac{2m_1v_1}{m_1+m_2}-\dfrac{(m_2-m_1)v_2}{m_2+m_1}

v_{gf} = \dfrac{2\times 0.11\times 31.5}{0.11+70}-\dfrac{(0.11-70)\times 0}{m_1+m_2}

v_{gf} = \dfrac{2\times 0.11\times 31.5}{0.11+70}

v_{gf} = 0.0988\ m/s

4 0
3 years ago
If an object is propelled upward from a height of 128 feet at an initial velocity of 112 feet per​ second, then its height h aft
Marina CMI [18]

Explanation:

The equation of motion of an object is given by :

h(t)=-16t^2+112t+128

Where

t is the time in seconds

We need to find the time when the object hits the ground. When the object hits the ground, h(t) = 0

So,

-16t^2+112t+128=0

-t^2+7t+8=0

On solving above equation using online calculator, t = 8 seconds. So, the object hit the ground after 8 seconds. Hence, this is the required solution.

8 0
3 years ago
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