Answer:
t_pass = 2.34 m
t_stop = 4.68 s
Thus, for the car passing at constant speed the pedestrian will have to wait less.
Explanation:
If the car is moving with constant speed, then the time taken by it will be given as:
where,
t_pass = time taken = ?
D = Distance covered = 23 m
v = constant speed = (22 mi/h)(1609.34 m/1 mi)(1 h/3600 s) = 9.84 m/s
Therefore,
<u>t_pass = 2.34 m</u>
<u></u>
Now, for the time to stop the car, we will use third equation of motion to get the acceleration first:
Now, for the passing time we use first equation of motion:
<u>t_stop = 4.68 s</u>
At the start, the ball is at rest and therefore, u=0 m/s. As it leaves the bat, v= 50 m/s
From equations of motion, v=u+at = at (since u=o)
a=v/t = 50/0.04 = 121250 m/s^2
From Newton's second law,
F=ma = 145/1000 *1250 = 181.25 N
Answer:
New days begin at 180° longitude.
Explanation: