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WITCHER [35]
3 years ago
14

Knowing the population standard deviation, a 95% confidence interval infers that the population mean ___________. is between 0 a

nd 100% is within ±1.96 standard deviations of the sample mean is within ±1.96 standard errors of the sample mean is too large
Mathematics
1 answer:
nevsk [136]3 years ago
3 0

Answer:

within ±1.96 standard deviations of the sample mean

Step-by-step explanation:

A 95% confidence interval is found using the formula C = 1 - α, and some other stuff, but let's focus on that for now. Using the formula:

.95 = 1 - α

α = .05

If α = .05, that means a 2-sided confidence interval would be found using the sample mean and the Z-score Z(subscript α/2), or Z.₀₂₅ because α AKA .05 divided by 2 = .025. From there, you take this either to your calculator or a Z-table (or perhaps you have a chart that lists the common CI values), and see that for the area to be .025 beneath a standard normal curve, your Z value is ±1.96 ("plus or minus" because we're considering a 2-sided confidence interval).

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Whats the difference between linear equations and quadratic equation
SIZIF [17.4K]

Answer:

Step-by-step explanation:

A linear equation in two variables doesn't involve any power higher than one for either variable. It has the general form Ax + By + C = 0, where A, B and C are constants. ... A quadratic equation, on the other hand, involves one of the variables raised to the second power. It has the general form y = ax2 + bx + c

4 0
3 years ago
How to find imaginary zeros anf real zeros of F(x)=-4x^5-8x^3+12x​
Fofino [41]

Answer:

x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}

Step-by-step explanation:

We are given the function:

f(x)=-4x^5-8x^3+12x

And we want to finds its zeros.

Therefore:

0=-4x^5-8x^3+12x

Firstly, we can divide everything by -4:

0=x^5+2x^3-3x

Factor out an x:

0=x(x^4+2x^2-3)

This is in quadratic form. For simplicity, we can let:

u=x^2

Then by substitution:

0=x(u^2+2u-3)

Factor:

0=x(u+3)(u-1)

Substitute back:

0=x(x^2+3)(x^2-1)

By the Zero Product Property:

x=0\text{ and } x^2+3=0\text{ and } x^2-1=0

Solving for each case:

x=0\text{ and } x=\pm\sqrt{-3}\text{ and } x=\pm\sqrt{1}

Therefore, our real and complex zeros are:

x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}

4 0
2 years ago
Evaluate 3x (2+6) divide 4 -2
kondaur [170]

Answer:

4

Step-by-step explanation:

Brackets always mean "DO THIS FIRST!!!"

2+6 = 8

Then, do 3 x 8. That is 24.

24 divided by 4 is 6.

6 - 2 is 4!

8 0
3 years ago
What is 7/10 + 7/10 =
Nonamiya [84]

The correct answer is 1.4 or 1 4/10

I did this by turning 7/10 into a decimal which is 0.7.

Now I just add 0.7 + 0.7.

For that equation i got 1.4

This would equal 1 4/10

3 0
3 years ago
Read 2 more answers
8 1/3 subtract 2 2/3
deff fn [24]

Answer:

5 2/3........................

4 0
2 years ago
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