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3 years ago

Please help show work?

Mathematics

2 answers:

Romashka-Z-Leto [24]3 years ago

5 0

Oh I get this.
So what you have to do is leave the same denominator and just count. Once a fraction has the same numerator and denominator that means it is a whole number.

mamaluj [8]3 years ago

3 0

Follow the same format as the examples on your paper.

1. 1/2 2/2 3/2 4/2 5/2 6/2 7/2 8/2 9/2 10/2

2. 1/2 1 1(1/2) 2 2(1/2) 3 3(1/2) 4 4(1/2 ) 5 5(1/2) 6

3. 1/3 2/3 3/3 4/3 5/3 6/3 7/3 8/3 9/3 10/3 11/3 12/3

4. 1/3 2/3 1 1(1/3) 1(2/3) 2 2(1/3) 2(2/3) 3 3(1/3) 3(2/3) 4

5. 1/4 2/4 3/4 4/4 5/4 6/4 7/4 8/4 9/4 10/4 11/4 12/4

6. 1/4 2/4 3/4 1 1(1/4) 1(2/4) 1(3/4) 2 2(1/4) 2(2/4) 2(3/4) 3

7. 1/4 1/2 3/4 1 1(1/4) 1(1/2) 1(3/4) 2 2(1/4) 2(1/2) 2(3/4) 3

8. 1/5 2/5 3/5 4/5 5/5 6/5 7/5 8/5 9/5 10/5 11/5 12/5

9. 1/5 2/5 3/5 4/5 1 1(1/5) 1(2/5) 1(3/5) 1(4/5) 2 2(1/5) 2(2/5)

10. 1/6 2/6 3/6 4/6 5/6 7/6 8/6 9/6 7/6 8/6 9/6 10/6 11/6 12/6

11. 1/6 2/6 3/6 4/6 5/6 1 1(1/6) 1(2/6) 1(3/6) 1(4/6) 1(5/6) 2

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I don't understand this question at all please help if you do

lorasvet [3.4K]

Answer:

Answer is $\frac{4}{3}$

Step-by-step explanation:

To find the interval of x. Use our equations to equal each other.

$-x^2+2x=y,y=0$

$-x^2+2x=0\\-x(x-2)=0\\-x=0 , (x-2)=0\\x=0 ,2$

$\int\limits^2_0 {-x^2+2x} \, dx$

Integrate.

$\frac{-x^3}{3}+x^2\\(\frac{-2^3}{3}+2^2)-[\frac{-0^3}{3}+0^2]\\-\frac{8}{3} +4-0\\-\frac{8}{3}+\frac{12}{3} =4/3$

Using Desmos I have Graphs of both of the equations you have provided. The problem asks us to find the shaded region between those curves/equations.

Proof Check your interval of x.

7 0

2 years ago

10. Please help. What is the length of ED⎯⎯⎯⎯⎯⎯⎯⎯?

DedPeter [7]

Answer:

The correct value is 12.

7 0

3 years ago

2. Determine whether each event is impossible,

Gre4nikov [31]

Answer:

likely is the awnser

Step-by-step explanation:

likely is the awnser

3 0

3 years ago

A total of 1 232 students have taken a course in Spanish, 879 have taken a course in French, and 114 have taken a course in Russ

ElenaW [278]

Answer:

$n(S\cap F \cap R)=7$

Step-by-step explanation:

The Universal Set, n(U)=2092

$n(S)=1232\\n(F)=879\\n(R)=114$

$n(S\cap R)=23\\n(S\cap F)=103\\n(F\cap R)=14$

Let the number who take all three subjects, $n(S\cap F \cap R)=x$

Note that in the Venn Diagram, we have subtracted $n(S\cap F \cap R)=x$ from each of the intersection of two sets.

The next step is to determine the number of students who study only each of the courses.

$n(S\:only)=1232-[103-x+x+23-x]=1106+x\\n(F\: only)=879-[103-x+x+14-x]=762+x\\n(R\:only)=114-[23-x+x+14-x]=77+x$

These values are substituted in the second Venn diagram

Adding up all the values

2092=[1106+x]+[103-x]+x+[23-x]+[762+x]+[14-x]+[77+x]

2092=2085+x

x=2092-2085

x=7

The number of students who have taken courses in all three subjects, $n(S\cap F \cap R)=7$

3 0

3 years ago

8^-3x^7y^-11/5x^-19y^17z^-14. Simplify

bazaltina [42]

Y^2/2560x^12z^14........................................

7 0

3 years ago