Answer:
By hypotenuse - side test (HL) the two triangles are congruent.
Step-by-step explanation:
In ∆ABC and ∆DCB
i) angleABC = angleDCB.....(each 90°)
ii) BC = BC .....( common side)
iii) AC = DB.....(given)
therefore by hypo-side test ∆ABC congruent ∆DCB
The binomial cumulative probability with p=0.5 for 3+ successes is as follows:

for p=0.5 (50% success rate) it becomes:

the probability is 0.65625, or about 66%
Answer:
You have 44$, your brother has 11$.
Step-by-step explanation:
Let
be the amount of money your brother has.
Since you have four times the amount of money your brother has, we can call the amount of money you have
.

Thus, you have:

Answer:
19.51% probability that none of them voted in the last election
Step-by-step explanation:
For each American, there are only two possible outcomes. Either they voted in the previous national election, or they did not. The probability of an American voting in the previous election is independent of other Americans. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
42% of Americans voted in the previous national election.
This means that 
Three Americans are randomly selected
This means that 
What is the probability that none of them voted in the last election
This is P(X = 0).
19.51% probability that none of them voted in the last election
Answer:
equation: 10 + 0.05x=22
Step-by-step explanation:
the next step after writing the equation would be to subtract 10 from both sides to get 0.05x=12. after this you would then have to divide 12 by 0.05 to get 240 minutes. you could check it by putting 240 in for x to get 10+0.05(240)=22. you would then multiply 0.05 by 240 to get 12 and then add 10 onto it to get 22 which was already given.