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Katena32 [7]
2 years ago
13

A spotlight on a 3.0 m stand shines on the surface of a swimming pool. The beam of light hits the water at a point 7.0 m away fr

om the base of the stand. Calculate the angle the beam makes with the pool surface.
Mathematics
1 answer:
Ede4ka [16]2 years ago
8 0

The angle the beam makes with the pool surface is 29.72°.

Step-by-step explanation:

<u>Data:</u>

The spotlight and surface of a swimming pool makes a 90 degree angle.

Spotlight stand is 3m (Opposite)

Beam of light hits the water 7m away from the base of light (base)

Angle = ?

<u>Use sin to solve</u>

Formula:

Tan (Angle) = \frac{Opposite}{Base}

Solution:

Sin (Angle) = \frac{3}{7}

Angle = tan^{-1} (0.571)

Angle = 29.72°

Therefore, the angle the beam makes with the pool surface is 29.72°.

Keyword: Angle

Learn more about angle at

  • brainly.com/question/4354581
  • brainly.com/question/4767370

#LearnwithBrainly

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7 0
3 years ago
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The mean preparation fee H&amp;R Block charged retail customers in 2012 was $183 (The Wall Street Journal, March 7, 2012). Use t
astraxan [27]

Answer:

a)0.6192

b)0.7422

c)0.8904

d)at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

Step-by-step explanation:

Let z(p) be the z-statistic of the probability that the mean price for a sample is within the margin of error. Then

z(p)=\frac{ME*\sqrt{N}}{s } where

  • Me is the margin of error from the mean
  • s is the standard deviation of the population
  • N is the sample size

a.

z(p)=\frac{8*\sqrt{30}}{50 } ≈ 0.8764

by looking z-table corresponding p value is 1-0.3808=0.6192

b.

z(p)=\frac{8*\sqrt{50}}{50 } ≈ 1.1314

by looking z-table corresponding p value is 1-0.2578=0.7422

c.

z(p)=\frac{8*\sqrt{100}}{50 } ≈ 1.6

by looking z-table corresponding p value is 1-0.1096=0.8904

d.

Minimum required sample size for 0.95 probability is

N≥(\frac{z*s}{ME} )^2 where

  • N is the sample size
  • z is the corresponding z-score in 95% probability (1.96)
  • s is the standard deviation (50)
  • ME is the margin of error (8)

then N≥(\frac{1.96*50}{8} )^2 ≈150.6

Thus at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

7 0
3 years ago
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tatuchka [14]

Answer (least to greatest):

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  4. 15/10
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I hope this helps!

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3 years ago
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Ulleksa [173]

Answer:

Step-by-step explanation:

Volumes of two spheres A and B = 648 cm³ and 1029 cm³

Things to remember:

1). Scale factor of two objects = \frac{r_1}{r_2} [r_1 and r_2 are the radii of two circles]

2). Area scale factor = \frac{(r_1)^2}{(r_2)^2}

3). Volume scale factor = \frac{(r_1)^3}{(r_2)^3}

Volume scale factor Or Volume ratio = \frac{V_A}{V_B}

                         \frac{(r_1)^3}{(r_2)^3}= \frac{648}{1029}

                         \frac{r_1}{r_2}=\sqrt[3]{\frac{648}{1029} }

                         \frac{r_1}{r_2}=\frac{6(\sqrt[3]{3})}{7(\sqrt[3]{3})}

                        \frac{r_1}{r_2}=\frac{6}{7}

Therefore, scale factor = \frac{r_1}{r_2}=\frac{6}{7}

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Area scale factor Or area ratio = (\frac{r_1}{r_2})^2=(\frac{6}{7})^2

                                                   = \frac{36}{49}

                                                   ≈ 36 : 49

Volume scale factor or Volume ratio = \frac{648}{1029}

                                                             = \frac{216}{343}

                                                             ≈ 216 : 343

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