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Alecsey [184]
3 years ago
14

Could someone answer these 3 questions?h

Mathematics
1 answer:
Aleks04 [339]3 years ago
8 0
9) x= -6
10) x= 3/2
11) x= -4,0,5
12) no solution
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a gardener plants 36 tomato vines in 2 hours at this rate how many tomato Vines can the gardener plant in 5 hours
Bumek [7]

The Correct Answer is 90


First find out how many in 1 hour so do

36÷2 to get 18

(36 Tomato Vines in 2 Hours)


Then do

18×5 to get 90

6 0
3 years ago
Shelia's measured glucose level one hour after a sugary drink varies according to the normal distribution with μ = 117 mg/dl and
TiliK225 [7]

Answer:

The level L such that there is probability only 0.01 that the mean glucose level of 6 test results falls above L is L = 127.1 mg/dl.

Step-by-step explanation:

To solve this problem, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 117, \sigma = 10.6, n = 6, s = \frac{10.6}{\sqrt{6}} = 4.33

What is the level L such that there is probability only 0.01 that the mean glucose level of 6 test results falls above L ?

This is the value of X when Z has a pvalue of 1-0.01 = 0.99. So X when Z = 2.33.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

2.33 = \frac{X - 117}{4.33}

X - 117 = 2.33*4.33

X = 127.1

The level L such that there is probability only 0.01 that the mean glucose level of 6 test results falls above L is L = 127.1 mg/dl.

6 0
3 years ago
Explain how you can rename 5,400 as hundreds.
balandron [24]

Answer:

The correct answer would be 54 hundreds

Step-by-step explanation:

If we are considering how many hundreds something has, we can simply take away two 0's and use that number.  We take the two 0's off and then we have the right number of hundreds

7 0
3 years ago
Read 2 more answers
What is the value of x?<br><br> 3 • (–4) • x = 0<br><br> x =
dedylja [7]
Multiply out
remember thatn (-) times (+)=(-) so
+3 times -4=-12
-12x=0
the only number that will work is 0 since 0 times anything=0

x=0
5 0
3 years ago
Read 2 more answers
Subtract the cube root of the product of h and 3k from the square of the sum of p and q​
ehidna [41]

Answer:

(p + q)²            -          ∛(h·3k)   or   (p + q)² - ∛(h·3k)  

Step-by-step explanation:

Cube root of x:  ∛x

Product of h and 3k:  h·3k

Sum of p and q:  p + q

*****************************

From (p + q)²      subtract ∛(h·3k)      This becomes, symbolically:

=>       (p + q)²            -          ∛(h·3k)

3 0
3 years ago
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