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Iteru [2.4K]
3 years ago
12

What does erosion do to land forms and to sediment

Physics
1 answer:
Ne4ueva [31]3 years ago
5 0
Well it breaks it away from rain or earthqukes depends but then depostion takes the rocks away and a delta takes it into the ocean
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What is an independent variable
snow_tiger [21]

Answer:

A variable (often denoted by x ) whose variation does not depend on that of another.

Explanation:

8 0
3 years ago
during conversion water to ice,forces of attraction between molecules. OPTIONS:1.)Decreases 2.)Increases 3.)Does not change 4.)C
In-s [12.5K]

because water is loosely packed but when it is cold it becomes closely packed in order to form ice and thus the force attraction between them also increase.

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3 years ago
What is the correct filing order for the following four names? (1) Washington Savings Bank (2) Washington State Credit Union (3)
docker41 [41]

Answer:

3,4,1,2

Explanation:

The filing procedure involves Filing in terms of the first letter.If the first letters are common, file in terms of the second letter then File in terms of surnames.If the surnames are common, file in terms of the initial. If the surname is more than one then file under the first surname etc.

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3 years ago
Which of the following is a high wave that crashes down onto the
andrew-mc [135]
A breaker is a high wave that crashes onto the ocean floor.
4 0
3 years ago
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Scientists plan to release a space probe that will enter the atmosphere of a gaseous planet. The temperature of the gaseous plan
lianna [129]

Answer: E. 450 K

Explanation:

It is given that the temperature of the gaseous planet is linearly related with height of the atmosphere. we can write this in the mathematical equation:

y = m x +c

where y is the temperature values, x is height, m is the slope and c is the y-intercept. we have been given two sets of value in the image, using which we can find the value of slope in y-intercept.

at x = 18.40 km, y = 147.54 K

⇒147.54 = 18.40 m + c      

⇒c = 147.54 - 18.40 m  ..(1)

at x =78.11 km, y = 567.00 K

⇒567.00 =78.11 m + c       ..(2)

Put equation 1 in 2 and solve:

⇒567.00 =78.11 m + 147.54 - 18.40 m

⇒419.46 = 59.71 m

⇒ m =419.46 ÷59.71 = 7.025 K/km

c = 147.54 - 18.40 × 7.025 = 18.28 K

At height, x = 61.5 km the approximate temperature is :

y = 7.025 K/km ×  61.5 km + 18.28 K = 450.3 K

Thus, the approximate temperature at altitude 61.5 km is 450 K.

8 0
4 years ago
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