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Deffense [45]
3 years ago
7

We can model a lightning bolt as a very long, straight wire. If a lightning bolt carries a current of 30 kA, and you are unfortu

nate enough to be 8.9 m away from the lightning bolt, how large of a magnetic field do you experience
Physics
1 answer:
Liula [17]3 years ago
8 0

Answer:

Magnetic field experienced = 4.5 × 10⁻⁴ T

Explanation:

The magnetic field around an infinite straight current-carrying wire at a distance r from the wire is given by

B = (μ₀I)/(2πr)

B = ?

I = 20 KA = 20000 A

r = 8.9 m

μ₀ = magnetic permeability = 1.257 × 10⁻⁶ T.m/A

B = (1.257 × 10⁻⁶ × 20000)/(2π×8.9) = 4.5 × 10⁻⁴ T

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It would be A. Because think of the explanations Jasons friend could say to them that would be a negative 'statement'.
7 0
3 years ago
A boy throws a stone straight upward with an initial
Dominik [7]

Answer:

14.8m

Explanation:

Given parameters:

Initial speed  = 17m/s

Unknown:

Maximum height  = ?

Solution:

At the maximum height, the final speed will be 0m/s;

 We use of the kinematics equation to solve this problem.

     V²   = U²   - 2gH

V is the final velocity

U is the initial velocity

g is the acceleration due to gravity

H is the height

         0²   = 17²  -  (2  x 9.8 x h )

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         -289  = -19.6h

            h  = 14.8m

5 0
3 years ago
A force of 0.2 Newtons is required to slide a book across the table. The book accelerates at 0.11 m/s squared. What is the mass
adelina 88 [10]
My calculations state, not rounding, the mass is 1.8
3 0
3 years ago
A freight train rolls along a track with considerable momentum. If it were to roll at the same speed but had twice as much mass,
fomenos

Answer:

The momentum would be doubled

Explanation:

The magnitude of the momentum of the freight train is given by:

p=mv

where

m is the mass of the train

v is its speed

In this problem, we have that the speed of the train is unchanged, while the mass of the train is doubled:

m'=2m

therefore, the new momentum is

p'=m'v=(2m)v=2(mv)=2p

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7 0
3 years ago
1. Two-point charges, QA = +8 μC and QB = -5 μC, are separated by a distance r = 10 cm. What is the magnitude and direction of t
tiny-mole [99]

Explanation:

Charges,q_1=8\ \mu C=8\times 10^{-6}\ C

q_2=-5\ \mu C=-5\times 10^{-6}\ C

The distance between charges, r = 10 cm = 0.1 m

We need to find the magnitude and direction of the electric force. It is given by :

F=\dfrac{kq_1q_2}{r^2}\\\\F=\dfrac{9\times 10^9\times 8\times 10^{-6}\times 5\times 10^{-6}}{(0.1)^2}\\\\F=36\ N

So, the required force between charges is 36 N and it is towards positive charge i.e. +8 μC.

6 0
3 years ago
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