Answer:
Q = 913.9 gpm
Explanation:
The Hazen Williams equation can be written as follows:

where,
P = Friction Loss per foot of pipe =
= 4 x 10⁻⁴
Q = Flow Rate in gallon/min (gpm) = ?
d = pipe diameter in inches = (400 mm)(0.0393701 in/1 mm) = 15.75 in
C = roughness coefficient = 100
Therefore,

<u>Q = 913.9 gpm</u>
Answer:
He could jump 2.6 meters high.
Explanation:
Jumping a height of 1.3m requires a certain initial velocity v_0. It turns out that this scenario can be turned into an equivalent: if a person is dropped from a height of 1.3m in free fall, his velocity right before landing on the ground will be v_0. To answer this equivalent question, we use the kinematic equation:

With this result, we turn back to the original question on Earth: the person needs an initial velocity of 5 m/s to jump 1.3m high, on the Earth.
Now let's go to the other planet. It's smaller, half the radius, and its meadows are distinctly greener. Since its density is the same as one of the Earth, only its radius is half, we can argue that the gravitational acceleration g will be <em>half</em> of that of the Earth (you can verify this is true by writing down the Newton's formula for gravity, use volume of the sphere times density instead of the mass of the Earth, then see what happens to g when halving the radius). So, the question now becomes: from which height should the person be dropped in free fall so that his landing speed is 5 m/s ? Again, the kinematic equation comes in handy:

This results tells you, that on the planet X, which just half the radius of the Earth, a person will jump up to the height of 2.6 meters with same effort as on the Earth. This is exactly twice the height he jumps on Earth. It now all makes sense.
Answer:
Centripetal acceleration,

Explanation:
Centripetal acceleration:
Centripetal acceleration is the idea that any object moving in a circle, in something called circular motion, will have an acceleration vector pointed towards the center of that circle.
Centripetal means towards the center.
Examples of centripetal acceleration (acceleration pointing towards the center of rotation) include such situations as cars moving on the cicular part of the road.
An acceleration is a change in velocity.
Formula for Centripetal acceleration:

Given here,
Velocity = 4.5 m/s
radius = 7.7 m
To Find :

Solution:
We have,

Substituting given value in it we get

Centripetal acceleration,

Answer:
The moment of inertia about an axis through the center and perpendicular to the plane of the square is

Explanation:
From the question we are told that
The length of one side of the square is 
The total mass of the square is 
Generally the mass of one size of the square is mathematically evaluated as

Generally the moment of inertia of one side of the square is mathematically represented as

Generally given that
it means that this moment inertia evaluated above apply to every side of the square
Now substituting for 
So

Now according to parallel-axis theorem the moment of inertia of one side of the square about an axis through the center and perpendicular to the plane of the square is mathematically represented as
![I_a = I_g + m [\frac{q}{2} ]^2](https://tex.z-dn.net/?f=I_a%20%3D%20%20I_g%20%2B%20m%20%5B%5Cfrac%7Bq%7D%7B2%7D%20%5D%5E2)
=> ![I_a = I_g + {\frac{M}{4} }* [\frac{q}{2} ]^2](https://tex.z-dn.net/?f=I_a%20%3D%20%20I_g%20%2B%20%7B%5Cfrac%7BM%7D%7B4%7D%20%7D%2A%20%5B%5Cfrac%7Bq%7D%7B2%7D%20%5D%5E2)
substituting for 
=> ![I_a = \frac{1}{12} * \frac{M}{4} * a^2 + {\frac{M}{4} }* [\frac{q}{2} ]^2](https://tex.z-dn.net/?f=I_a%20%3D%20%20%5Cfrac%7B1%7D%7B12%7D%20%20%2A%20%20%5Cfrac%7BM%7D%7B4%7D%20%2A%20a%5E2%20%2B%20%7B%5Cfrac%7BM%7D%7B4%7D%20%7D%2A%20%5B%5Cfrac%7Bq%7D%7B2%7D%20%5D%5E2)
=> 
=> 
Generally the moment of inertia of the square about an axis through the center and perpendicular to the plane of the square is mathematically represented as

=> 
=> 