All categories

3 years ago

P waves and S waves are alike in that they __________.

2 answers:

7 0

The correct answer that would best complete the given statement above would be the first option. P waves and S waves are alike in that they travel in the same manner. P and S waves are the categories of the vibrations of earthquakes. They both travel in the Earth's surface. Hope this answer helps.

sammy [17]3 years ago

3 0

<h3>Answer;</h3>

travel through solids

P waves and S waves are alike in that they both travel through solids.

<h3>Explanation;</h3>

P-waves and S-waves are types of seismic waves. These waves are produced during an earthquake, that transmit energy released around the earth.
P-waves travel the fastest and also travel through solids, liquids and gases. They are push and pull waves and thus they cause rock particles to move back and forth.
S-wave son the other hand arrive at a given point after the p-waves. They do not travel as fast as P-waves. They travel through solids but not in liquids and gases. S -waves cause the rocks to move side to side.

You might be interested in

Name the plate boundary responsible for this. Please help!!

Korolek [52]

Continental crust plate name

5 0

3 years ago

Read 2 more answers

You are sitting in a chair on an elavator. The elavator accelerates downward, you and the chair land on the cround with the chai

ExtremeBDS [4]

Answer:

fdsbgdfshtrsnbfgsbnhgr

Explanation:

cdfrgresgtrshtrwhtrwhtwjhdgngdabfeahydrtgnb

7 0

3 years ago

A fish takes the bait and pulls on the line with a force of 2.3 N. The fishing reel, which rotates without friction, is a unifor

natulia [17]

Explanation:

The given data is as follows.

Pulling force on the reel is F = T = 2.3 N

Mass of cylinder (m) = 0.82 kg

Radius of cylinder (r) = 0.045 m

Formula for torque pulling force on the cylinder is as follows.

$\tau = Fr$

= $I \times \alpha$

Moment of inertia of the cylinder (I) is as follows.

I = $\frac{mr^{2}}{2}$

$\alpha$ = angular acceleration of the cylinder

Hence,

Fr = $(\frac{mr^{2}}{2}) \alpha$

or, $\alpha = \frac{2F}{mr}$

= $\frac{2 \times 2.3 N}{0.82 kg \times 0.045 m}$

= 124.66 $rad/s^{2}$

Amount of line pulled is h and it is in a times of 0.2 sec.

Now, linear acceleration is calculated as follows.

a = $r \alpha$

= $0.045 m \times 124.66 rad/s^{2}$

= 5.61 $m/s^{2}$

Now, relation between h and acceleration as follows.

h = $v_{o}t + \frac{1}{2}at^{2}$

here, $v_{o}$ = 0

Hence, calculate the value of h as follows.

h = $v_{o}t + \frac{1}{2}at^{2}$

= $0 + \frac{1}{2} \times 5.61 m/s^{2} \times (0.2s)^{2}$

= 0.1121 m

Thus, we can conclude that acceleration of the fishing reel is 5.61 $m/s^{2}$ and it will pull 5.61 $m/s^{2}$ line from the reel in 0.20 s.

7 0

4 years ago

Read 2 more answers

Two streams merge to form a river. One stream has a width of 8.3 m, depth of 3.2 m, and current speed of 2.2 m/s. The other stre

katovenus [111]

Answer:

The depth of the resulting stream is 3.8 meters.

Explanation:

Under the assumption that streams are formed by incompressible fluids, so that volume flow can observed conservation:

$\dot V_{1} + \dot V_{2} = \dot V_{3}$ (1)

All volume flows are measured in cubic meters per second.

Dimensionally speaking, we can determine the depth of the resulting stream ( $h_{3}$ ), in meters, by expanding (1) in this manner:

$w_{1}\cdot h_{1}\cdot v_{1} + w_{2}\cdot h_{2}\cdot v_{2} = w_{3}\cdot h_{3}\cdot v_{3}$

$h_{3} = \frac{w_{1}\cdot h_{1}\cdot v_{1}+w_{2}\cdot h_{2}\cdot v_{2}}{w_{3}\cdot v_{3}}$ (2)

$v_{1}, v_{2}$ - Speed of the merging streams, in meters per second.

$h_{1}, h_{2}$ - Depth of the merging streams, in meters.

$w_{1}, w_{2}$ - Width of the merging streams, in meters.

$w_{3}$ - Width of the resulting stream, in meters.

$v_{3}$ - Speed of the resulting stream, in meters per second.

If we know that $w_{1} = 8.3\,m$ , $h_{1} = 3.2\,m$ , $v_{1} = 2.2\,\frac{m}{s}$ , $w_{2} = 6.8\,m$ , $h_{2} = 3.2\,m$ , $v_{2} = 2.4\,\frac{m}{s}$ , $w_{3} = 10.4\,m$ and $v_{3} = 2.8\,\frac{m}{s}$ , then the depth of the resulting stream is:

$h_{3} = \frac{(8.3\,m)\cdot (3.2\,m)\cdot \left(2.2\,\frac{m}{s} \right) + (6.8\,m)\cdot (3.2\,m)\cdot \left(2.4\,\frac{m}{s} \right)}{(10.4\,m)\cdot \left(2.8\,\frac{m}{s} \right)}$

$h_{3} = 3.8\,m$

The depth of the resulting stream is 3.8 meters.

3 0

3 years ago

The planet Neptune is the farthest planet from the Sun. A satellite is orbiting around Neptune at a distance of 180 km. As the s

stich3 [128]

2,992² + r² = ( r + 180 )²
8,952,064 + r² = r² + 360 r + 32,400
360 r = 8,952,064 - 32,400
360 r = 8,919,664
r = 8,919,664 : 360
r = 24,776.844 km
d = 24,776.844 · 2 = 49,553688 ≈ 49,554 km
Answer:
The approximate diameter of the planet Neptune is 49,554 km.

4 0

3 years ago