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uranmaximum [27]
3 years ago
12

The number of hours a group of contestants spends preparing for a quiz show is listed below. What is the frequency table that re

presents that data?
8 12 25 32 45 50 62 73 80 99 4 18 9 39 36 67 33
Mathematics
1 answer:
harkovskaia [24]3 years ago
8 0
I'll just show you how to make a frequency table using the above data. 
We will group the data into class intervals and determine the frequency of the group.

<span>8 12 25 32 45 50 62 73 80 99 4 18 9 39 36 67 33
</span>
smallest data value = 4
highest data value = 99
difference = 99 - 4 = 95
number of data = 17

Let us assign a class interval of 20.

Class Interval     Tally                              Frequency
0-20                    8, 12, 4, 18, 9,                     5
21-40                25, 32, 39, 36, 33                 5 
41-60                45, 50, 67                              3
61-80                62, 73, 80                              3
81-100              99                                           1

That is how a frequency table look like. Usually, under the Tally column, tick marks are written instead of the numbers but for easier monitoring, I used the numbers in the data set.
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(4-m-1)-5

Remove the bracket

= 4-m-1-5

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7 0
3 years ago
I need help QUICK! with this difficult question
likoan [24]

Answer:

Step-by-step explanation:

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3 years ago
Suppose the object moving is Dave, who hasamassofmo =66kgatrest. Whatis Daveâs mass at 90% of the speed of light? At 99% of the
nignag [31]

Step-by-step explanation:

Formula that relates the mass of an object at rest and its mass when it is moving at a speed v:

m=\frac{m_o}{\sqrt{1-\frac{v^2}{c^2}}}

Where :

m = mass of the oebjct in motion

m_o = mass of the object when at rest

v = velocity of a moving object

c = speed of the light = 3\times 0^8 m/s

We have :

1) Mass of the Dave = m_o=66 kg

Velocity of Dave ,v= 90% of speed of light = 0.90c

Mass of the Dave when moving at 90% of the speed of light:

m=\frac{66 kg}{\sqrt{1-\frac{(0.90c)^2}{c^2}}}

m = 151.41 kg

Mass of Dave when when moving at 90% of the speed of light is 151.41 kg.

2) Velocity of Dave ,v= 99% of speed of light = 0.99c

Mass of the Dave when moving at 99% of the speed of light:

m=\frac{66 kg}{\sqrt{1-\frac{(0.99c)^2}{c^2}}}

m = 467.86 kg

Mass of Dave when when moving at 99% of the speed of light is 467.86 kg.

3) Velocity of Dave ,v= 99.9% of speed of light = 0.999c

Mass of the Dave when moving at 99.9% of the speed of light:

m=\frac{66 kg}{\sqrt{1-\frac{(0.999c)^2}{c^2}}}

m = 1,467.17 kg

Mass of Dave when when moving at 99.9% of the speed of light is 1,467.17 kg.

4) Mass of the Dave = m_o=66 kg

Velocity of Dave,v=?

Mass of the Dave when moving at v speed of light: 500

500 kg=\frac{66 kg}{\sqrt{1-\frac{(v)^2}{(3\times 10^8 m/s)^2}}}

v=2.973\times 10^8 m/s

Dave should be moving at speed of 2.973\times 10^8 m/s.

4 0
3 years ago
A recipe for banana oat muffins calls for 3/4 cups of oats. You need to triple the recipe to make enough for your whole family.
Marta_Voda [28]

Answer: 2 and 1/4 cups of oats (9/4 cups of oats)

Step-by-step explanation:

We know that, for the recipe, we need 3/4 cups of oats.

Now, you want to triple the recipe (then you need to use 3 times more ingredients).

This means that, if for the recipe you needed 3/4 cups of oats, when we triple that we have:

3*(3/4 cups) = 9/4 cups

This means that you need to use 9/4 cups of oats.

And we could also write this as:

9/4 cups = 8/4 cups + 1/4 cups = 2 + 1/4 cups of oats.

3 0
3 years ago
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