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Westkost [7]
2 years ago
13

En salón de clases hay 30 alumnos; el 40% son hombres y el 60% son mujeres ¿Cuántos hombres y mujeres hay en el salón de clases?

Mathematics
1 answer:
vodomira [7]2 years ago
4 0

There are 30 students in the classroom; 40% are men and 60% are women. How many men and women are in the classroom?

40/100 = 2/5   60/100 = 3/5   30 ÷ 5 = 6   3 × 6 = 18 so 18 are women 2 × 6 = 12

so there are 12 men.

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HELPSolve for x<br> X =<br> A: 1<br> B: 3<br> C: 7
OverLord2011 [107]

X equals 7

Hope that helped

7 0
3 years ago
In the system –12c + 3d = 6 and –3c + 6d = –9, which expression could you use for substitution?
Jlenok [28]
3d is the answer if I am wrong please let me know

5 0
2 years ago
2(4 - 2r) = -2(r + 5)
Alexus [3.1K]
2(4 - 2r) = -2(r + 5)

First, divide both sides by -2. / Your problem should look like: -4 + 2r = r + 5
Second, regroup your terms. / Your problem should look like: 2r - 4 = r + 5
Third, add 4 to both sides. / Your problem should look like: 2r = r + 5  + 4
Fourth, add r + 5 + 4 to get r + 9. / Your problem should look like:2r = r + 9
Fifth, subtract r from both sides. / Your problem should look like: 2r - r = 9
Sixth, subtract 2r - r to get r. / Your problem should look like: r = 9

Answer: r = 9

5 0
3 years ago
Read 2 more answers
Two cables support a 800​-lb ​weight, as shown. Find the tension in each cable.
jeka94

Answer:

  • 892 lb (right)
  • 653 lb (left)

Step-by-step explanation:

The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...

  Rcos(45°) +Lcos(75°) = 800

  Rsin(45°) -Lsin(75°) = 0

Solving these equations by Cramer's Rule, we get ...

  R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))

     = 800sin(75°)/sin(120°) ≈ 892 . . . pounds

  L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds

The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.

_____

This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...

  (right, left) = w/sin(α+β)×(sin(β), sin(α))

5 0
2 years ago
Mr. Juarez opened a savings account with an initial deposit of $560 and will not make any additional deposits or withdrawals. Th
olga_2 [115]

Answer:

$576.80

Step-by-step explanation:

We have been given that Mr. Juárez opened a savings account with an initial deposit of $560 and will not make any additional deposits or withdrawals. The account earns 1% simple interest.

We are asked to find the total amount that Mr. Juárez will have in his account at the end of 3 years.

We will use simple interest formula to solve our given problem.

A=P (1+rt)

A = Final amount after t years,

P = Principal amount,

r = Annual interest rate in decimal form,

t = Time in years.

Let us convert 1% into decimal form,

1%=1/100=0.01

P=$560 and t=3

A=$560 (1+0.01(3))

A=$560 (1+0.03)

A= $560 (1.03)

A= $576.80

Therefore, Mr. Juárez will have $576. 80 in his account at the end of 3 years. Hope this helps!

5 0
3 years ago
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