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notka56 [123]
1 year ago
10

PLEASE HELP ASAP (QUICK MATH QUESTION)

Mathematics
1 answer:
Mama L [17]1 year ago
4 0

The given identity sin(x+ y) - sin (x- y) = 2 cos x sin y  has been verified

The identity is

sin(x+ y) - sin (x- y) = 2 cos x sin y

Here we have to use the trigonometric function

Consider the right hand side of the equation

We know

sin (x+ y) = sin x cos y + cos x sin y

sin (x-y) = sin x cos y - cos x sin y

Then

sin(x+ y) - sin (x- y) = sin x cos y + cos x sin y - (sin x cos y - cos x sin y)

= sin x cos y + cos x sin y - sin x cos y + cos x sin y

Eliminate the terms

= cos x sin y + cos x sin y

= 2 cos x sin y

Hence, the given identity sin(x+ y) - sin (x- y) = 2 cos x sin y  has been verified

Learn more about trigonometric function here

brainly.com/question/14746686

#SPJ1

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Given f(x)=1/x+5 and g(x)=x-2
vladimir1956 [14]

For this case we have the following functions:

f (x) = \frac {1} {x + 5}\\g (x) = x-2

We must find f (g (x)). So:

f (g (x)) = \frac {1} {(x-2) +5} = \frac {1} {x-2 + 5} = \frac {1} {x + 3}

Finally we have to:

f (g (x)) = \frac {1} {x + 3}

For the function to be defined the denominator must be different from 0. That is x different from -3.

Answer:

Option B

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Answer:

I got this. Use the order PEMDAS search Up if you don’t know what it means.

Step-by-step explanation:

Start with What’s inside the parentheses

(X - 3) = 3x

(X + 5) = 5x

The divide.

How to divide it - The number coefficients are reduced the same as in simple fractions. When dividing variables, you write the problem as a fraction. Then, using the greatest common factor, you divide the numbers and reduce. You use the rules of exponents to divide variables that are the same — so you subtract the powers.

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I NEED HELP ASAP PLEASE DON'T SPAM :(​
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Answer:

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Step-by-step explanation:

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Yesterday noah ran 2 1/2 miles in 3/5 hour. Emily ran 3 3/4 miles in 5/6 hour. Anna ran 3 1/2 miles in 3/4 hour how fast in mile
Dmitry_Shevchenko [17]

Answer:

Step-by-step explanation:

To calculate the speed of each one we proceed as follows:

speed=distance/time

a] Noah's speed:

distance=2.5 miles

time=3/5 hours

speed=(2 1/2)/(3/5)

=(5/2)/(3/5)

=5/2×5/3

=25/6

=4 1/6 mi/hr

Emily's speed

distance=3 3/4 miles

time=5/6 hour

thus

speed=(3 3/4)/(5/6)

=15/4)/(5/6)

=15/4×6/5

=4 1/2 mi/hr

Anna's speed:

distance=3 1/3 miles

time=3/5

speed=(3 1/3)/(3/5

=(10/3)/(3/5)

=10/3×5/3

=5 5/9 mi/hr

Anna was the fastest

6 0
3 years ago
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Write and equation for the shift of the parent graph y=1/x
SashulF [63]
You can think of this equation as \bf f(x)=\cfrac{1}{x}\implies f(x)=(x)^{-1}

and thus apply the transformations to it as such

\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}\\\\
--------------------\\\\

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\

\bf \bullet \textit{ vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

1)  D = 2, C = +3

2) D = -12, C = -2

3) C = +6, D = 3

4) C = -7, D = -7
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