Answer:
P = f(TLTL) = 0,16
H = f(TLTS) = 0,48
Q = f(TSTS) = 0,36
Explanation:
Hello!
The allele proportion of any locus defines the genetic constitution of a population. Its sum is 1 and its values can vary between 0 (absent allele) and 1 (fixed allele).
The calculation of allelic frequencies of a population is made taking into account that homozygotes have two identical alleles and heterozygotes have two different alleles.
In this case, let's say:
f(TL) = p
f(TS) = q
p + q = 1
Considering the genotypes TLTL, TLTS, TSTS, and the allele frequencies:
TL= 0,4
TS= 0,6
Genotypic frequency is the relative proportion of genotypes in a population for the locus in question, that is, the number of times the genotype appears in a population.
P = f(TLTL)
H = f(TLTS)
Q = f(TSTS)
Also P + H + Q = 1
And using the equation for Hardy-Weinberg equilibrium, the genotypic frequencies of equilibrium are given by the development of the binomial:
![p^{2} = f(TLTL)](https://tex.z-dn.net/?f=p%5E%7B2%7D%20%3D%20f%28TLTL%29)
![2pq = f(TSTL)](https://tex.z-dn.net/?f=2pq%20%3D%20f%28TSTL%29)
![q^{2} = f(TSTS)](https://tex.z-dn.net/?f=q%5E%7B2%7D%20%3D%20f%28TSTS%29)
So, if the population is in balance:
![P = p^{2}](https://tex.z-dn.net/?f=P%20%3D%20p%5E%7B2%7D)
![H = 2pq](https://tex.z-dn.net/?f=H%20%3D%202pq)
![Q = q^{2}](https://tex.z-dn.net/?f=Q%20%3D%20q%5E%7B2%7D)
Replacing the given values of allele frecuencies in each equiation you can calculate the expected frequency of each genotype for the next generation as:
![f(TLTL) = P = p^{2} = 0,4^{2} = 0,16](https://tex.z-dn.net/?f=f%28TLTL%29%20%3D%20P%20%3D%20p%5E%7B2%7D%20%3D%200%2C4%5E%7B2%7D%20%3D%200%2C16)
![f(TLTS) = H = 2pq = 2*0,4*0,6 = 0,48](https://tex.z-dn.net/?f=f%28TLTS%29%20%3D%20H%20%3D%202pq%20%3D%202%2A0%2C4%2A0%2C6%20%3D%200%2C48)
![f(TSTS) = Q = q^{2} = 0,6^{2} = 0,36](https://tex.z-dn.net/?f=f%28TSTS%29%20%3D%20Q%20%3D%20q%5E%7B2%7D%20%3D%200%2C6%5E%7B2%7D%20%3D%200%2C36)
I hope you have a SUPER day!
Answer:
Must be able to reproduce.
Explanation:
All organism are able to reproduce.
This is called the G1 phase I'm sure.
Answer:
If Clark had no ions in his nervous system, he would not be able to generate an action potentials.
Explanation:
An action potential occurs when a stimulus causes sodium channels to open in a neuron. Sodium floods in, making the inside of the cell more negative and the outside more positive. This is known as depolarization. Then, the Potassium channels open to allow Potassium out (Repolarization). A few too many K+ ions will leave the cell (Hyperpolarization), and finally, the Sodium-Potassium pump will bring the cell back to resting potential.
As you can see, the Sodium and Potassium ions are <em>essential</em> to action potentials in the nervous system. If Clark had no ions in his system, he would not be able to send any action potentials at all.
Do you have a chart that you are able to add or post?