In 1995, the moose population in a park was measured to be 4200. By 1998, the population was measured again to be 1600. If the p
2 answers:
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Answer:
The 99% confidence interval of the population mean for the weights of adult elephants is between 12,475 pounds and 12,637 pounds.
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 10 - 1 = 9
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of . So we have T = 3.25
The margin of error is:
M = T*s = 3.25*25 = 81
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 12,556 - 81 = 12,475 pounds
The upper end of the interval is the sample mean added to M. So it is 12,556 + 81 = 12,637 pounds.
The 99% confidence interval of the population mean for the weights of adult elephants is between 12,475 pounds and 12,637 pounds.
Answer:
Depth = 3.3 inches
Step-by-step explanation:
Given that the shape of the satellite looks like a parabola
The equation of parabola is given as follows
Where
a= 13
Therefore
Lets take (13 , y) is a
Now by putting the values in the above equation we get
y=3.25 in
Therefore the depth of the satellite at the nearest integer will be 3.3 inches.
Depth = 3.3 inches
