Answer: 16 is your answer hope this helped
Step-by-step explanation:
pleas make brainly
The mean absolute deviation of a number set is the average distance between each value and the mean.<span> This is obtained by finding the mean of the set, determining the absolute value difference between each number, and the mean and calculating the average of these differences.
The mean of the set is ( 26 + 43 + 48 + 29 + 16 + 30 ) / 6 = 32 ;
</span> the absolute value difference between each number:
/ 26 - 32 / = 6 ; / 43 - 32 / = 11 ; / 48 - 32 / = 16 ; / 29 - 32 / = 3 ; / 16 - 32 / = 16 ;
/ 30 - 32 / = 2 ;
the mean absolute deviation of 26 43 48 29 16 30 is ( 6 + 11 + 16 + 3 + 16 + 2 ) / 6 = 9 ;
Please note that your x^3/4 is ambiguous. Did you mean (x^3) divided by 4
or did you mean x to the power (3/4)? I will assume you meant the first, not the second. Please use the "^" symbol to denote exponentiation.
If we have a function f(x) and its derivative f'(x), and a particular x value (c) at which to begin, then the linearization of the function f(x) is
f(x) approx. equal to [f '(c)]x + f(c)].
Here a = c = 81.
Thus, the linearization of the given function at a = c = 81 is
f(x) (approx. equal to) 3(81^2)/4 + [81^3]/4
Note that f '(c) is the slope of the line and is equal to (3/4)(81^2), and f(c) is the function value at x=c, or (81^3)/4.
What is the linearization of f(x) = (x^3)/4, if c = a = 81?
It will be f(x) (approx. equal to)
Answer:
^7√(-4)^2 or 1.48 I hope it helps
Answer:
d= 17.03
Step-by-step explanation:
