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sergiy2304 [10]
3 years ago
11

Line segment AB was translated 2 units right and 7 units down to create line segment CD. A transversal intersects the two line s

egments, as shown in the graph below.
Select all of the true statements.

--Since ∠3 and ∠4 are corresponding angles, they are congruent.
-- Line segments AB and CD are parallel.
--Since ∠1 and ∠2 are corresponding angles, they are congruent.
-- Line segments AB and CD are perpendicular.
--Since ∠1 and ∠4 are alternate interior angles, they are congruent.
---Since ∠1 and ∠3 are corresponding angles, they are congruent.

Mathematics
1 answer:
belka [17]3 years ago
6 0
These are correct statements:

<span>- Line segments AB and CD are parallel.

- </span>Since ∠1 and ∠3 are corresponding angles, they are congruent.
These are incorrect statements:

- <span>Since ∠3 and ∠4 are corresponding angles, they are congruent. They are not corresponding angles, they are supplementary meaning they, together, equal 180.

- </span><span>Since ∠1 and ∠2 are corresponding angles, they are congruent. These are also not corresponding, they are supplementary.

- </span><span>Line segments AB and CD are perpendicular. They are not crossing over each other.</span>

- <span>Since ∠1 and ∠4 are alternate interior angles, they are congruent. They are not corresponding, they are supplementary. </span><span>∠1 and </span><span>∠3 are corresponding just like </span>∠2 and <span>∠4. </span>






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Martin wants to use coordinate geometry to prove that the opposite sides of
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The correct answer is option A which is the distance between A and D will be  AD = \sqrt{(0-0)^2-(b-0)^2}=\sqrt{b^2}=b.

<h3>What is coordinate geometry?</h3>

A coordinate plane is a 2D plane which is formed by the intersection of two perpendicular lines known as the x-axis and y-axis.

The formula utilised to find the distance between two points is;-

X = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2

We have the coordinates of the point A = (0, 0) and D is  (0, b).By applying the formula to find the distance between A and D.

AD = \sqrt{(0-0)^2-(b-0)^2}=\sqrt{b^2}=b.

Therefore the correct answer is option A which is the distance between A and D will be  AD = \sqrt{(0-0)^2-(b-0)^2}=\sqrt{b^2}=b.

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4 0
2 years ago
Which equation is true when the value of x is -12
Sophie [7]

Answer:

Which equation is true when the value of x is -12    HERE YOU GO!!

Step-by-step explanation:

tricky ... let's see ...

I notice that if we subtract xy from both sides we get

7x + xy - xy = xy - xy + 21

then

7x = 21

and

x = 21/7 = 3

so there is only one value of x that satisfies the equation

x = 3

Going back to the original equation we see that any value of y will satisfy the original equation

we can see this by rearranging things:

7x + xy - xy = 21

here, I have performed the subtraction of xy on the right side as above, but have left the left side undone

(so we don't lose the presence of y)

Note that the above can also be written as

7x + (x - x)y = 21

or

7x + 0y =21

now, since anything times zero equals zero,

y may be any number.

Let's summarize:

1) x = 3

2) y = anything

looking back at the original question;

1) the equation is true for all ordered pairs

FALSE (only one x works, not all x)

2) there are no x and y pairs for which the equation is true.

FALSE (x=3, y=anything) makes it true, i.e. (3,1)  

3) For each value of x, there is one and only one value of y that makes the equation true,

FALSE for each value of x, for the one value of x, x=3, y can be any number, which is an infinite number, not one

4) for each value of y, there is one and only on value of x that makes the equation true.

TRUE!! for all the infinite values of y you may pick, there is one and only one x you may pick, x = 3

ANSWER: STATEMENT 4 is CORRECT (TRUE)

3 0
3 years ago
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Answer:

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Step-by-step explanation:

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(i just changed my answer)

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