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DaniilM [7]
3 years ago
9

I need help with this please

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
7 0
Answer:

3) 0 ≤ y ≤ 100
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The difference of 20 and x
Anni [7]

Answer:

20-x

Step-by-step explanation:

you need the value of x to answer

8 0
2 years ago
If I Row my canoe at 5 mph and I travel upstream at 3 mph, how fast will I be traveling downstream if I am rowing at the same ra
Assoli18 [71]
Is the same as the one you just did.

keep in mind that, going against the current, the current's speed erodes speed from your regular speed, whilst if you're going with the current, the current's speed adds to it.

now, in this case, you row 5mph, going upstream you're only doing 3mph, whatever happened to the other 2mph?  well, the current speed eroded them, meaning the speed of the river is 2mph.

now, going downstream with the current, your regular speed is 5mph, and the current is 2mph, since the current adds to yours, then you're going 5 + 2, mph.
5 0
3 years ago
Find the inverse of y=log(-2x)
kodGreya [7K]

Answer:f

−

1

(

x

Step-by-step explanation:

5 0
3 years ago
A factory can work its employees no more than 6 days a week, and no less than 2 days per
Molodets [167]

Answer:

Step-by-step explanation:

Answer: A.) 2 <= X <= 6

B.) 13 < = X < = 39

Step-by-step explanation:

Given that a factory can work its employees no more than 6 days a week, that is, less than or equal to 6 days a week

And also, no less than 2 days per week. That is, greater than or equal to 2 day a week.

Let X represent the number of days an employee can work per week.

According to the first statement,

X < = 6

According to the second statement,

X >= 2

An inequality to represent the range of days an employee can work will be

2 < = X <= 6

To represent the range in hours, first convert the number of days to hour. Given that an employee can work

1 day = 6.5 hours

2 days = 2 × 6.5 = 13 hours

5 days = 6 × 6.5 = 39 hours

Therefore, the range will be

13 < = X < = 39

6 0
3 years ago
Two numbers have prime factorizations of 2 2 · 3 · 5 and 2 · 3 2 · 7.
ladessa [460]
I think for the question above, instead of 2 · 3^2 · 7 it is <span>2 · 3^2 · 5.
</span>
Two numbers have prime factorizations of 2^2 • 3 • 5 and 2 • 3^2 • 5 (note 2 squared & 3 squared).

Now, to choose the GCF, you choose, for each base factor in either number, the least exponent-ed one; so the GCF needs a factor 2, a factor 3, and a factor 5. Thus the GCF is 30 (their product). [i.e,2 squared is not a common factor]

<span>To create the LCM, you choose, for each base factor in either number, the greatest exponented one. Thus, LCM needs a factor 2 squared, 3 squared, and 5, giving LCM = 4(9)(5) = 180.</span><span />
4 0
3 years ago
Read 2 more answers
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