Using the speed - distance relationship, the time left before the appointed time is 27 minutes.
<u>Recall</u><u> </u><u>:</u>
<u>At</u><u> </u><u>10mph</u><u> </u><u>:</u>
- Distance = 10 × (t + 3) = 10t + 30 - - - (1)
<u>At</u><u> </u><u>12</u><u> </u><u>mph</u><u> </u><u>:</u>
- Distance = 12 × (t - 2) = 12t - 24 - - - - (2)
<em>Equate</em><em> </em><em>(</em><em>1</em><em>)</em><em> </em><em>and</em><em> </em><em>(</em><em>2</em><em>)</em><em> </em><em>:</em>
10t + 30 = 12t - 24
<em>Collect</em><em> </em><em>like</em><em> </em><em>terms</em><em> </em>
10t - 12t = - 24 - 30
-2t = - 54
<em>Divide</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>by</em><em> </em><em>-</em><em> </em><em>2</em>
t = 54 / 2
t = 27
Hence, the time left before the appointed time is 27 minutes.
Learn more : brainly.com/question/25669152
Answer:u fill in 4 tiles
It’s a 4x5 square so there is 20 tiles
And 20 divided by 4 equals 5
So if u fill in 4 tiles it’s like filling in 1/5 aka 20%
Answer:
0.767 m
Step-by-step explanation:
The area of a cube of edge length s is given by ...
A = 6s^2
The area of a sphere of radius r is given by ...
A = 4πr^2
When these two are equal, we have ...
6s^2 = 4πr^2
r^2 = 6s^2/(4π)
r = s·√(3/(2π)) ≈ s·0.690988
The radius of the sphere is about ...
r ≈ 0.690899×1.11 m
r ≈ 0.767 m . . . . approximate sphere radius
Step-by-step explanation:
Since sides AD and BC are parallel,
Angle BAD + Angle ADC = 180° (co-interior angles)
Therefore Angle ADC = 180° - 115° = 65°.