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Leona [35]
3 years ago
14

The value of a semi-trailer when new is $625 000. The value of the semi-trailer depreciates by

Mathematics
1 answer:
Nina [5.8K]3 years ago
4 0

Answer:

$546,875

Step-by-step explanation:

if the trailer brand new costs $625,000 and decreases by 12.5% you want to find 10% which is $62,500. then you want to find 5% which would be $31,250. but you want 2.5% so you need to divide $31,250 by 2 which is $15,625. add $62,500 and $15,625 together which is $78,125. then do $625,000-$78,625 which gets you $546,875.

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Zanzabum
Your question wasn't posted clearly.
It would be difficult to help you.

\rm x^3y^2-8x^3y~16x^3y^5-8y^416y^3
It's all one big mess.
Was it supposed to be two or three separate expressions?
3 0
3 years ago
If someone could please help me, I want to make sure that the steps are correct.
Leya [2.2K]
Your answer would be the last option, c = √(E/m).

We can see this when we rearrange the equation, as:

E = mc²
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E/m = c²
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So you got all the steps in rearranging correct :)


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7 0
3 years ago
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yarga [219]

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7 0
3 years ago
Which number doesn't belong?<br> 9 16 25<br> 43
Alex

Answer:

43

Step-by-step explanation:

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Square root of 16 is 4

Square root of 25 is 5

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8 0
3 years ago
Read 2 more answers
Multiple-choice questions each have four possible answers left parenthesis a , b , c , d right (a, b, c, d)​, one of which is co
arlik [135]
A) Since there are four multiple choice questions Which has one correct answer. The probability of choosing a correct answer is

P(C) = \frac{1}{4}

The probability of choosing wrong answer is

P(W) = \frac{3}{4}

Using the multiplication rule
P(WWC) = P(W) \times P(W) \times P(C) \\ \\ P(WWC) = \frac{3}{4} \times \frac{3}{4} \times \frac{1}{4} \\ \\ P(WWC) = \frac{9}{64}

b) If you guess answers to three of the questions, then the possibilities of getting one correct answer are:

Either the first two are wrong and the third one is correct. This will give the arrangement;

WWC

Or the first is wrong the second one is correct and the last one is wrong. This will give the arrangement,

WCW

Or the first one is correct and the last two are wrong. This will give the arrangement,

CWW
.

P(WWC) = P(W) \times P(W) \times P(C) \\ \\ P(WWC) = \frac{3}{4} \times \frac{3}{4} \times \frac{1}{4} \\ \\ P(WWC) = \frac{9}{64}

P(WCW ) = P(W) \times P( C ) \times P(W) \\ \\ P(WCW) = \frac{3}{4} \times \frac{1}{4} \times \frac{3}{4} \\ \\ P(WCW) = \frac{9}{64}

P(CWW ) = P(W) \times P( C ) \times P(W) \\ \\ P(CWW) = \frac{1}{4} \times \frac{3}{4} \times \frac{3}{4} \\ \\ P(CWW) = \frac{9}{64}

c) The probability of getting one correct answer is either the first one is correct or second is correct or third is correct.

P(One \: Correct)= P(CWW) \: or P(WCW) \: or \: P(WWC) \\ \\ P(One \: Correct)= P(CWW) \: + P(WCW) \: + \: P(WWC) \\ \\ P(One \: Correct)= \frac{9}{64} + \frac{9}{64} + \frac{9}{64}  \\ \\ P(One \: Correct) = \frac{27}{64}
7 0
4 years ago
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