D =√(x2-x1)^2 + (y2-y1)^2
......._____________
5 =√(3-0)^2 + (k-1)^2
.......__________
5 =√3^2 + (k-1)^2
25 = 9 + (k-1)^2
16 = k^2 - 2k + 1
k^2 -2k - 15 = 0
(k - 5)(k + 3) = 0
k - 5 = 0.....or.......(k + 3) = 0
k = 5.........or.......k = -3
Answer: 3.1
Step-by-step explanation:
44 minutes and 24 seconds
Answer:
Although the Line is included in the region, I will say the your answer is B and D
Step-by-step explanation:
The region shaded is below the Line graph, son we have a < sign, now, I can see the region including the Line graph, so I will say that the inequality should have the = sign, nevertheless no options include the =sign, so, if it is nothing missing, your answer should be:
y<x
X= a number
(2x+4)/3 + (x+2)= 20
Multiply everything by 3 to eliminate the fraction
(3/1)((2x+4)/3) + (3)(x+2)= (3)(20)
2x+4+3x+6= 60
5x+10=60
Subtract 10 from both sides
5x=50
divide both sides by 5
x=10
Check:
Substitute answer in original equation
(2x+4)/3 + (x+2)= 20
(2(10)+4)/3+(10+2)= 20
(20+4)/3+12= 20
24/3+12= 20
8+12= 20
20=20
Hope this helps! :)
