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3 years ago

2(3x - 1) + 2(4x + 5) = 8

Mathematics

2 answers:

professor190 [17]3 years ago

7 0

Distribute as we get,

$[(3x*2)-(2*1)]+[(4x*2)+(5*2)]=8\\(6x-2)+(8x+10)=8$

Remove the brackets,

$6x-2+8x+10=8$

Then combine,

$14x+8=8$

Move +8 to the right side and change the +8 to -8 (The operator must be the opposite when move to the other side.)

$14x=8-8\\14x=0$

Move 14 to the right side so we can find the value of x. (Because it's x multiply 14 then 0 will be divided by 14.)

$x=\frac{0}{14}$

Therefore, x = 0.

tigry1 [53]3 years ago

3 0

Answer:

x=0

Step-by-step explanation:

2(3x - 1) + 2(4x + 5) = 8

Distribute

6x -2 +8x +10 =8

Combine like terms

14x +8 = 8

Subtract 8 from each side

14x+8-8=8-8

14x =0

Divide each side by 14

14x/14 = 0/14

x=0

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