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3 years ago

A group of people were asked if they had run a red light in the last year. 248 responded "yes", and 106 responded "no".

Mathematics

1 answer:

aliina [53]3 years ago

3 0

Answer:

Im confused what are u supposed to do ?

Step-by-step explanation:

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Determine whether each expression is equivalent to 49^2t – 0.5.

vampirchik [111]

Answer:

None of the expression are equivalent to $49^{(2t - 0.5)}$

Step-by-step explanation:

Given

$49^{(2t - 0.5)}$

Required

Find its equivalents

We start by expanding the given expression

$49^{(2t - 0.5)}$

Expand 49

$(7^2)^{(2t - 0.5)}$

$7^2^{(2t - 0.5)}$

Using laws of indices: $(a^m)^n = a^{mn}$

$7^{(2*2t - 2*0.5)}$

$7^{(4t - 1)}$

This implies that; each of the following options A,B and C must be equivalent to $49^{(2t - 0.5)}$ or alternatively, $7^{(4t - 1)}$

A. $\frac{7^{2t}}{49^{0.5}}$

Using law of indices which states;

$a^{mn} = (a^m)^n$

Applying this law to the numerator; we have

$\frac{(7^{2})^{t}}{49^{0.5}}$

Expand expression in bracket

$\frac{(7 * 7)^{t}}{49^{0.5}}$

$\frac{49^{t}}{49^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{49^{t}}{49^{0.5}}$ becomes

$49^{t-0.5}}$

This is not equivalent to $49^{(2t - 0.5)}$

B. $\frac{49^{2t}}{7^{0.5}}$

Expand numerator

$\frac{(7*7)^{2t}}{7^{0.5}}$

$\frac{(7^2)^{2t}}{7^{0.5}}$

Using law of indices which states;

$(a^m)^n = a^{mn}$

Applying this law to the numerator; we have

$\frac{7^{2*2t}}{7^{0.5}}$

$\frac{7^{4t}}{7^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{7^{4t}}{7^{0.5}}$ = $7^{4t - 0.5}$

This is also not equivalent to $49^{(2t - 0.5)}$

C. $7^{2t}\ *\ 49^{0.5}$

$7^{2t}\ *\ (7^2)^{0.5}$

$7^{2t}\ *\ 7^{2*0.5}$

$7^{2t}\ *\ 7^{1}$

Using law of indices which states;

$a^m*a^n = a^{m+n}$

$7^{2t+ 1}$

This is also not equivalent to $49^{(2t - 0.5)}$

6 0

3 years ago

A train moving at a speed of 75 km/hr covers a certain distance in 4.8 hours.

kakasveta [241]

Answer:

Step-by-step explanation:

Distance=Speed×Time

75×4.8=360

Speed=distance÷time

360÷3=120km/h

6 0

3 years ago

How will the area of the circle change if it is dilated by a scale factor of 1/2? The area will be 2 times greater than the orig

coldgirl [10]

We know that

[scale factor]=1/2
[dilated area of circle]=[original area of circle]*[scale factor]²
so
[dilated area of circle]=[original area of circle]*[1/2]²
[dilated area of circle]=[original area of circle]*[1/4]

therefore

the answer is
<span>The area will be 1/4 the original</span>

7 0

3 years ago

Read 2 more answers

the height of a tree was 12 feet. after a year, the tree's height increased 25%. what is the height of the tree after a year

Margaret [11]

Answer:

15 feet

Step-by-step explanation:

7 0

3 years ago

Using substitution, identify it the given point is a solution of the given linear inequality.

yuradex [85]

Answer:

Step-by-step explanation:

substitute the values from (x,y) into the equation.

3(-1)+2(2)>6

-3+4>6

1>6

false

3 0

3 years ago