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vladimir1956 [14]
3 years ago
6

A group of people were asked if they had run a red light in the last year. 248 responded "yes", and 106 responded "no".

Mathematics
1 answer:
aliina [53]3 years ago
3 0

Answer:

Im confused what are u supposed to do ?

Step-by-step explanation:

You might be interested in
Determine whether each expression is equivalent to 49^2t – 0.5.
vampirchik [111]

Answer:

None of the expression are equivalent to 49^{(2t - 0.5)}

Step-by-step explanation:

Given

49^{(2t - 0.5)}

Required

Find its equivalents

We start by expanding the given expression

49^{(2t - 0.5)}

Expand 49

(7^2)^{(2t - 0.5)}

7^2^{(2t - 0.5)}

Using laws of indices: (a^m)^n = a^{mn}

7^{(2*2t - 2*0.5)}

7^{(4t - 1)}

This implies that; each of the following options A,B and C must be equivalent to 49^{(2t - 0.5)} or alternatively, 7^{(4t - 1)}

A. \frac{7^{2t}}{49^{0.5}}

Using law of indices which states;

a^{mn} = (a^m)^n

Applying this law to the numerator; we have

\frac{(7^{2})^{t}}{49^{0.5}}

Expand expression in bracket

\frac{(7 * 7)^{t}}{49^{0.5}}

\frac{49^{t}}{49^{0.5}}

Also; Using law of indices which states;

\frac{a^{m}}{a^n} = a^{m-n}

\frac{49^{t}}{49^{0.5}} becomes

49^{t-0.5}}

This is not equivalent to 49^{(2t - 0.5)}

B. \frac{49^{2t}}{7^{0.5}}

Expand numerator

\frac{(7*7)^{2t}}{7^{0.5}}

\frac{(7^2)^{2t}}{7^{0.5}}

Using law of indices which states;

(a^m)^n = a^{mn}

Applying this law to the numerator; we have

\frac{7^{2*2t}}{7^{0.5}}

\frac{7^{4t}}{7^{0.5}}

Also; Using law of indices which states;

\frac{a^{m}}{a^n} = a^{m-n}

\frac{7^{4t}}{7^{0.5}} = 7^{4t - 0.5}

This is also not equivalent to 49^{(2t - 0.5)}

C. 7^{2t}\ *\ 49^{0.5}

7^{2t}\ *\ (7^2)^{0.5}

7^{2t}\ *\ 7^{2*0.5}

7^{2t}\ *\ 7^{1}

Using law of indices which states;

a^m*a^n = a^{m+n}

7^{2t+ 1}

This is also not equivalent to 49^{(2t - 0.5)}

6 0
3 years ago
A train moving at a speed of 75 km/hr covers a certain distance in 4.8 hours.
kakasveta [241]

Answer:

Step-by-step explanation:

Distance=Speed×Time

75×4.8=360

Speed=distance÷time

360÷3=120km/h

6 0
3 years ago
How will the area of the circle change if it is dilated by a scale factor of 1/2? The area will be 2 times greater than the orig
coldgirl [10]
We know that

[scale factor]=1/2
[dilated area of circle]=[original area of circle]*[scale factor]²
so
[dilated area of circle]=[original area of circle]*[1/2]²
[dilated area of circle]=[original area of circle]*[1/4]

therefore

the answer is
<span>The area will be 1/4 the original</span>
7 0
3 years ago
Read 2 more answers
the height of a tree was 12 feet. after a year, the tree's height increased 25%. what is the height of the tree after a year
Margaret [11]

Answer:

15 feet

Step-by-step explanation:

7 0
3 years ago
Using substitution, identify it the given point is a solution of the given linear inequality.
yuradex [85]

Answer:

no

Step-by-step explanation:

substitute the values from (x,y) into the equation.

3(-1)+2(2)>6

-3+4>6

1>6

false

3 0
2 years ago
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