A group of people were asked if they had run a red light in the last year. 248 responded "yes", and 106 responded "no".

OLEGan [10]

Answer: w = 12

Step-by-step explanation: In this problem, we want to get w by itself on one side of the equation. Since we have 14 + W, in order to get w by itself, we must subtract 14 from the left side of the equation.

If we subtract 14 from the left side of the equation, we must also subtract 14 from the right side of the equation. So on the left, +14 and -14 cancel each other and on the right, 26 - 14 simplifies to 12 so w = 12.

To check our answer, we substitute a 12 back in for w in the original equation and we have 14 + (12) = 26 or 26 = 26 which is a true statement so the answer checks.

6 0

3 years ago

Marie will earn $15 per hour at a new job. During training, she will earn $10 per hour. What percent of Marie’s regular hourly r

Hitman42 [59]

Answer: 66.67%

Step-by-step explanation:

Given: The amount Marie will earn at a new job = $15 per hour

The amount she will earn during the training = $10 per hour

The percent of Marie’s regular hourly rate she will earn during training is given by :-

$P=\frac{\text{Rate of amount she earn in training }}{\text{Rate of amount she earn at new job }}\times100\\\\\Rightarrow\ P=\frac{10}{15}\times100\\\\\Rightarrow\ P=66.66666\%\approx66.67\%$

4 0

2 years ago

There are moles in 1.26 × 1024 particles.

EastWind [94]

Answer:

1.26 x 10^(24)

Step-by-step explanation:

hope this helped

6 0

3 years ago

Explain which graph is best for a teacher who wants to know the range of scores for the bottom 25%, the middle 50% and the top 2

Scrat [10]

A quadratic graph. It makes an upside down U shape

8 0

2 years ago

Complete parts (a) through (c) below. (a) Determine the critical value(s) for a right-tailed test of a population mean at t

olga_2 [115]

Answer:

a) The critical value on this case would be $t_{crit}=1.325$

b) The critical value on this case would be $t_{crit}=-1.345$

c) The critical values on this case would be $t_{crit}=\pm 2.201$

Step-by-step explanation:

Part a

The system of hypothesis on this case would be:

Null hypothesis: $\mu \leq \mu_0$

Alternative hypothesis: $\mu > \mu_0$

Where $\mu_0$ is the value that we want to test.

In order to find the critical value we need to find first the degrees of freedom, on this case that is given df=20. Since its an upper tailed test we need to find a value a such that:

$P(t_{20}>a) = 0.1$

And we can use excel in order to find this value with this function: "=T.INV(0.9,20)". The 0.9 is because we have 0.9 of the area on the left tail and 0.1 on the right.

The critical value on this case would be $t_{crit}=1.325$

Part b

The system of hypothesis on this case would be:

Null hypothesis: $\mu \geq \mu_0$

Alternative hypothesis: $\mu < \mu_0$

Where $\mu_0$ is the value that we want to test.

In order to find the critical value we need to find first the degrees of freedom, given by:

$df=n-1=15-1=14$

Since its an lower tailed test we need to find b value a such that:

$P(t_{14}$

And we can use excel in order to find this value with this function: "=T.INV(0.1,14)". The 0.1 is because we have 0.1 of the area accumulated on the left of the distribution.

The critical value on this case would be $t_{crit}=-1.345$

Part c

The system of hypothesis on this case would be:

Null hypothesis: $\mu = \mu_0$