Answer:
See below.
Step-by-step explanation:
a.
Divide the leading terms:
6x^4 / 2x^2 = 3x^2
3x2 is a parabola so the long run is
as x ---> +/- infinity r(x) ----> + infinity. (answer).
b.
10,000x^3 / 50 x^3
= 200.
So r(x) as a horizontal asymptote at y ( r(x)) = 200. (answer).
#1) 4.445 ft
#2) yes
Explanation
#1) The maximum height is the y-coordinate of the vertex. We first find the axis of symmetry, given by x=-b/2a:
x=-0.17/2(-0.005) = -0.17/-0.01 = 17
Plugging this into the equation,
y=-0.005(17²)+0.17(17)+3 = 4.445
#2) Substituting 30 into the equation,
y=-0.005(30²) + 0.17(30) + 3 = 3.6
The ball will 3.6 in the air, so yes, it will clear the 3 ft tall net.
Answer:
7. 7.8
Step-by-step explanation:
We can use Tan of this angle to find the missing side (in this case, the side adjacent to the angle measuring 57°)
Tan A = (opposite side)/(adjacent side)
Tan 57° = 12/x
solve for x
x(Tan 57°) = 12
x = 12/(Tan 57°)
x = 7.8 (rounded to the nearest tenth)
<span>We simplify the equation to the form, which is simple to understand
<span>4x+8-2x=20
We move all terms containing x to the left and all other terms to the right.
<span>+4x-2x=+20-8
We simplify left and right side of the equation.
<span>+2x=+12
We divide both sides of the equation by 2 to get x.
<span>x=6</span></span></span></span></span>
The answer is -
2x^2 + 2x + 7
