Answer:
The answer is a
Step-by-step explanation:
The distance from the near end of the runway to the plane, divided by the altitude is the tangent of (90 degrees minus the angle of depression). Let "d1" be the distance to the near end of the runway, and "d2" be the distance to the far end of the runway. Let "a" be the altitude of the plane.
d1/a = tan(90 - 31)
d1 = a*tan(90 - 31)
d2/a = tan(90 - 23)
d2 = a*tan(90 - 23)
runway length = d2 - d1 = a*(tan(67) - tan(59))
length = 1800*(.6916) = 1245m = 1.2km
the answer is "a"
Answer:
12/12
Step-by-step explanation:
I would say simply perform the division already indicated.
(16 in)/(12 h) = 16/12 in/h = 4/3 in/h
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Alternatively, divide the given rate by 1. The form 12/12 gives you the same thing as above:
(16 in)/(12 h)/(12/12) = (16/12) in/h = 4/3 in/h
-3v+24 would be your answer
Answer:
The answer is B. It often helps to look at the desmos website to input the graphs.
Step-by-step explanation:
You can see that the points (4,13) intersect the graphs y = 2/5x+23 as well as be perpendicular to y=2/5x-5.
