Question

Calculate the molarity of a solution made by diluting 0.083 L of 0.14 M HCl solution to a volume of 1.0 L. Enter your answer in scientific notation. Be sure to answer all parts. x 10 (select) M HCI

Answer 1

Explanation:

Molarity is defined as the number of moles of solute present in liter of solution.

Mathematically,         Molarity = $\frac{\text{no. of moles}}{\text{Volume in liter}}$

Also, when number of moles are equal in a solution then the formula will be as follows.

                     $M_{1} \times V_{1} = M_{2} \times V_{2}$

It is given that $M_{1}$ is 0.14 M, $V_{1}$ is 0.083 L, and $V_{2}$ is 1.0 L.

Hence, calculate the value of $M_{2}$ using above formula as follows.

                    $M_{1} \times V_{1} = M_{2} \times V_{2}$

                 $0.14 M \times 0.083 L = M_{2} \times 1.0 L$

                      $M_{2} = \frac{0.01162 M.L}{1 L}$

                                  = 0.01162 M

Thus, we can conclude that the molarity of a solution is 0.01162 M.