I believe you only need to know one angle.
For example, if you know angle 1, you can calculate angle 3. Angle 2 = angle 3 and angle 4 = angle 1.
Also, Angle 5= angle 1 and so on...
Answer:
l have no clue
Step-by-step explanation:
<span>You can probably just work it out.
You need non-negative integer solutions to p+5n+10d+25q = 82.
If p = leftovers, then you simply need 5n + 10d + 25q ≤ 80.
So this is the same as n + 2d + 5q ≤ 16
So now you simply have to "crank out" the cases.
Case q=0 [ n + 2d ≤ 16 ]
Case (q=0,d=0) → n = 0 through 16 [17 possibilities]
Case (q=0,d=1) → n = 0 through 14 [15 possibilities]
...
Case (q=0,d=7) → n = 0 through 2 [3 possibilities]
Case (q=0,d=8) → n = 0 [1 possibility]
Total from q=0 case: 1 + 3 + ... + 15 + 17 = 81
Case q=1 [ n + 2d ≤ 11 ]
Case (q=1,d=0) → n = 0 through 11 [12]
Case (q=1,d=1) → n = 0 through 9 [10]
...
Case (q=1,d=5) → n = 0 through 1 [2]
Total from q=1 case: 2 + 4 + ... + 10 + 12 = 42
Case q=2 [ n + 2 ≤ 6 ]
Case (q=2,d=0) → n = 0 through 6 [7]
Case (q=2,d=1) → n = 0 through 4 [5]
Case (q=2,d=2) → n = 0 through 2 [3]
Case (q=2,d=3) → n = 0 [1]
Total from case q=2: 1 + 3 + 5 + 7 = 16
Case q=3 [ n + 2d ≤ 1 ]
Here d must be 0, so there is only the case:
Case (q=3,d=0) → n = 0 through 1 [2]
So the case q=3 only has 2.
Grand total: 2 + 16 + 42 + 81 = 141 </span>
4 consecutive integers : (x), (x + 1), (x + 2), (x + 3)
x + x + 1 + x + 2 + x + 3 = 114...combine like terms
4x + 6 = 114....subtract 6 from both sides
4x = 114 - 6
4x = 108...divide both sides by 4
x = 108/4
x = 27
x + 1 = 27 + 1 = 28
x + 2 = 27 + 2 = 29
x + 3 = 27 + 3 = 30
so ur 4 numbers are : 27, 28, 29, 30
<h3>3 1/2 - 1 1/3 becomes</h3><h3>7/2 - 4/3 which becomes</h3><h3>21/6 - 8/6 = 13/6</h3><h3>13/6 = 2 1/6</h3><h3></h3><h3>ANSWER = 2 wholes 1/6</h3>
