4 in (4,-5) implies positive x-axis.
-5 in (4,-5) implies negative y-axis.
Since x is positive and y is negative in fourth quadrant, so the answer is
QUADRANT IV (or 4th quadrant.
Widths = 23.5feet
Lengths = 47feet
23.5 + 23.5 + 47 + 47 = 141
we have a maximum at t = 0, where the maximum is y = 30.
We have a minimum at t = -1 and t = 1, where the minimum is y = 20.
<h3>
How to find the maximums and minimums?</h3>
These are given by the zeros of the first derivation.
In this case, the function is:
w(t) = 10t^4 - 20t^2 + 30.
The first derivation is:
w'(t) = 4*10t^3 - 2*20t
w'(t) = 40t^3 - 40t
The zeros are:
0 = 40t^3 - 40t
We can rewrite this as:
0 = t*(40t^2 - 40)
So one zero is at t = 0, the other two are given by:
0 = 40t^2 - 40
40/40 = t^2
±√1 = ±1 = t
So we have 3 roots:
t = -1, 0, 1
We can just evaluate the function in these 3 values to see which ones are maximums and minimums.
w(-1) = 10*(-1)^4 - 20*(-1)^2 + 30 = 10 - 20 + 30 = 20
w(0) = 10*0^4 - 20*0^2 + 30 = 30
w(1) = 10*(1)^4 - 20*(1)^2 + 30 = 20
So we have a maximum at x = 0, where the maximum is y = 30.
We have a minimum at x = -1 and x = 1, where the minimum is y = 20.
If you want to learn more about maximization, you can read:
brainly.com/question/19819849
You could write 42/20 for #60.
Answer:
Both have the same y-intercept (-9)
Step-by-step explanation:
✔️Function 1, r = ⅝t - 9, is given in the slope-intercept form, y = mx + b.
b = y-intercept = -9
y-intercept for Function 1 = -9
✔️Function 2, using the table given, the y-intercept is the value of r when t = 0.
Thus, r = -9 when t = 0.
y-intercept for Function 2 = -9
✔️Both functions has the same y-intercept. None is greater than the other.
