Answer: D is the right answer
Step-by-step explanation:
Answer:
A= 306,87°
B= 196,26°
C= 112,62
Step-by-step explanation:
sinA =-4/5
A = -53,24°
A = 306,87°
tan B = 7/24
B = 16,26°
B = 196,26°
cos C = -5/13
C = 112,62°
To check whether there is a reason to believe that the average height has been changed, we can check one right-tailed test and establish null and alternate hypotheses.
H₀ (null hypothesis): μ = 162.5
H₁ (alternate hypothesis): μ > 162.5
Since we have two samples to compare, we can use the formula below to compute for the z-score.
![Z = \frac{(\chi - \mu)}{ \sigma / \sqrt{n}}](https://tex.z-dn.net/?f=%20Z%20%3D%20%5Cfrac%7B%28%5Cchi%20-%20%5Cmu%29%7D%7B%20%5Csigma%20%2F%20%5Csqrt%7Bn%7D%7D%20)
where Z is the z-score, Χ is the new mean of the sample, μ is the expected average value, δ is the standard deviation, and n is the sample size. Given the values we have,
![Z = \frac{(165.2 - 162.5)}{6.9 / \sqrt{50}}](https://tex.z-dn.net/?f=%20Z%20%3D%20%5Cfrac%7B%28165.2%20-%20162.5%29%7D%7B6.9%20%2F%20%5Csqrt%7B50%7D%7D%20)
![Z \approx 2.77](https://tex.z-dn.net/?f=%20Z%20%5Capprox%202.77%20)
Assuming that the significance level, α, is 0.05. Now that we have a z-score of 2.77, we can use the z-table to find its p-value. Thus, we have P(Z > 2.77) = .0028. Thus since our p-value is less than α, H₀ is rejected. That means that the average height of the female freshman students has changed.
Answer:location and distance from your workplace
Step-by-step explanation: