I think it would be 4.
8 breaks down to 4(2) and 12 breaks down to 4(3). Let me know if that helps!
I am pretty sure R is -19 meters and N is -7 and A is 476 AD
Answer:
The approximate are of the inscribed disk using the regular hexagon is 
Step-by-step explanation:
we know that
we can divide the regular hexagon into 6 identical equilateral triangles
see the attached figure to better understand the problem
The approximate area of the circle is approximately the area of the six equilateral triangles
Remember that
In an equilateral triangle the interior measurement of each angle is 60 degrees
We take one triangle OAB, with O as the centre of the hexagon or circle, and AB as one side of the regular hexagon
Let
M ----> the mid-point of AB
OM ----> the perpendicular bisector of AB
x ----> the measure of angle AOM

In the right triangle OAM

so

we have

substitute

Find the area of six equilateral triangles
![A=6[\frac{1}{2}(r)(a)]](https://tex.z-dn.net/?f=A%3D6%5B%5Cfrac%7B1%7D%7B2%7D%28r%29%28a%29%5D)
simplify

we have

substitute

Therefore
The approximate are of the inscribed disk using the regular hexagon is 
Well, since we know is a geometric sequence, we can always get the common ratio of it by simply dividing one value by the one behind it... so let's do so, with say hmm -32 and 8 -32/8 = -4 <-- our common ratio
the first term is -2
Answer:
1:44
Step-by-step explanation:
You can subtract 32 minutes from 2:32 to get 2:00.
Since you only subtracted 32, subtract 16 (16+32=48) from 60, since 60 minutes is one hour, to get 1:44