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Pie
3 years ago
13

Sam counted Out Loud by 6's Jorge counted Out Loud by 8s what are the first three numbers both Sam and George said

Mathematics
1 answer:
nadya68 [22]3 years ago
4 0
Sam's first three number:6,12,18 George's first three numbers:8,16,24
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Determine the greatest common factor of the following numbers 8 and 12<br>NO LINKS PLEASE!!!!​
jonny [76]
I think it would be 4.
8 breaks down to 4(2) and 12 breaks down to 4(3). Let me know if that helps!
3 0
3 years ago
I need help with these 3 please help!
diamong [38]
I am pretty sure R is -19 meters and N is -7 and A is 476 AD
3 0
3 years ago
Read 2 more answers
A disk with radius 3 units is inscribed in a regular hexagon. Find the approximate area of the inscribed disk using the regular
Oksi-84 [34.3K]

Answer:

The approximate are of the inscribed disk using the regular hexagon is A=18\sqrt{3}\ units^2

Step-by-step explanation:

we know that

we can divide the regular hexagon into 6 identical equilateral triangles

see the attached figure to better understand the problem

The approximate area of the circle is approximately the area of the six equilateral triangles

Remember that

In an equilateral triangle the interior measurement of each angle is 60 degrees

We take one triangle OAB, with O as the centre of the hexagon or circle, and AB as one side of the regular hexagon

Let

M  ----> the mid-point of AB

OM ----> the perpendicular bisector of AB

x ----> the measure of angle AOM

m\angle AOM =30^o

In the right triangle OAM

tan(30^o)=\frac{(a/2)}{r}=\frac{a}{2r}\\\\tan(30^o)=\frac{\sqrt{3}}{3}

so

\frac{a}{2r}=\frac{\sqrt{3}}{3}

we have

r=3\ units

substitute

\frac{a}{2(3)}=\frac{\sqrt{3}}{3}\\\\a=2\sqrt{3}\ units

Find the area of six equilateral triangles

A=6[\frac{1}{2}(r)(a)]

simplify

A=3(r)(a)

we have

r=3\ units\\a=2\sqrt{3}\ units

substitute

A=3(3)(2\sqrt{3})\\A=18\sqrt{3}\ units^2

Therefore

The approximate are of the inscribed disk using the regular hexagon is A=18\sqrt{3}\ units^2

6 0
3 years ago
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maks197457 [2]
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the first term is -2

\bf n^{th}\textit{ term of a geometric sequence}\\\\&#10;a_n=a_1\cdot r^{n-1}\qquad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;r=\textit{common ratio}\\&#10;----------\\&#10;a_1=-2\\&#10;r=-4&#10;\end{cases}\implies a_n=-2(-4)^{n-1}
4 0
3 years ago
kate takes 48 minutes to get to the park. if she gets to the park at 2:32 what time did she leave for the park
olya-2409 [2.1K]

Answer:

1:44

Step-by-step explanation:

You can subtract 32 minutes from 2:32 to get 2:00.

Since you only subtracted 32, subtract 16 (16+32=48) from 60, since 60 minutes is one hour, to get 1:44

8 0
2 years ago
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