Answer:
The answer is 3,064x
Explanation:
When the collision happens, the momentum of the first car is applied to the both of them.
So we can calculate the force that acts on both cars as:
- The momentum of the first car is P = 2020 kg x 14.2 m/s = 28,684 kg.m/s
- The acceleration of both cars after the crash is going to be a = P / mtotal which will give us a = 28,684 / (2020+2940) = 5.78 m/s
- Since the second car was initially not moving, the final acceleration was calculated with the momentum of the first car.
Now we can find the force that acts on both of them by using the formula F = m.a which will give us the result as:
- F = (2020+2940) x 5.78 = 28,684
The friction force acts in the opposite direction and if they stop after moving 2.12 meters;
- Friction force is Ff = μ x N where μ is the friction coefficient and the N is the normal force which is (2020+2940) x 10 if we take gravitational force as 10, equals to 49,600.
- F - Ffriction = m x V
- 28,684 - μ x 49,600 = 4960 x 5.78
- μ = 3,064x

Answer:
1.- para cubrir la superficie lateral 4.32 metros²
2.- Area de la base 2.15 metros²
3.- Volumen 1 m³
4.- Area total 6.47 metros²
Explanation:
El área lateral sera calcular el area de seis triangulos iguales cuya base es
0.80 de base x 6 lados = 4.80 metros perimetro de la base
4.80 perimetro de base x 1.80 arista lateral / 2 = 4.32m2
Area de la base:
Perímetro x Apotema / 2
Siendo la Apotema la altura de los triangulos que componen un hexagono calculada utilizando el teorema de pitágoras:

Apotema = 0.894427191
Area: 4.80 x 0.894427191 / 2 = 2.146625258
sumando el area de la base mas el area lateral se obtiene el area total
2.15 + 4.32 = 6.47 metros
Volumen de la pirámide:
Area de la Base x Altura / 3
2.15 x 1.40 / 3 = 1.00333 m3
Answer:
When it is marked with its cubic-inch volume
Explanation:
Because this allows for best and efficient identification