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2 years ago

What are Sir Issac Newton's three laws of motion?

2 answers:

4 0

The first law is that every object stay at rest or stay in uniform motion in a straight line until it is forced to change its state by the action of an external force. This law is called law of inertia.

The second law is that the acceleration of an object is dependent upon two variables. the net force acting upon the object and the mass of the object. F= ma or force is equal to mass times acceleration. This law is known as the law of force and acceleration.

The third law is that for every action there is an equal and opposite reaction. every interaction there is a pair of forces acting on the two interacting objects. the size of forces on the first object equals the size of the force on the second object.

Hope this helps :)

can you please make this the brainliest answer it would really help . Thanks

tino4ka555 [31]2 years ago

4 0

Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. ... The third law states that for every action (force) in nature there is an equal and opposite reaction.

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What can you conclude about the total mechanical energy of a pendulum as it swings back and forth?

Alchen [17]

Answer:

The total mechanical energy of a pendulum is conserved neglecting the friction.

Explanation:

When a simple pendulum swings back and forth, it has some energy associated with its motion.
The total energy of a simple pendulum in harmonic motion at any instant of time is equal to the sum of the potential and kinetic energy.
The potential energy of the simple pendulum is given by P.E = mgh
The kinetic energy of the simple pendulum is given by, K.E = 1/2mv²
When the pendulum swings to one end, its velocity equals zero temporarily where the potential energy becomes maximum.
When the pendulum reaches the vertical line, its velocity and kinetic energy become maximum.
Hence, the total mechanical energy of a pendulum as it swings back and forth is conserved neglecting the resistance.

8 0

3 years ago

A minivan is tested for acceleration and braking. In the street-start acceleration test, the elapsed time is 8.6 s for a velocit

Varvara68 [4.7K]

The question is incomplete. Here is the complete question:

A minivan is tested for acceleration and braking. In the street-start acceleration test, the elapsed time is 8.6 s for a velocity increase from 10 km/h to 100 km/h. In the braking test, the distance traveled is 44 m during braking to a stop from 100 km/h. Assume constant values of acceleration and deceleration. Determine

(a) the acceleration during the street-start test,

(b) the deceleration during the braking test.

Answer:

(a) 37500 km/h²

(b) 113636.36 km/h²

Explanation:

part (a)

Because it is given that we can assume constant acceleration therefore we can use the following equation of motion:

where <em>v </em>is final velocity, <em>u </em>is initial velocity, <em>a </em>is acceleration and <em>t </em>is time change

Given in the question:

v = 100km/h

u = 10 km/h

t = 8.6 sec (changing to hours)

t = 0.0024 hours (round off to 4 decimal places)

100 = 10 + (a x 0.0024)

Rearranging the equation to find value of a

a = (100 – 10) / 0.0024

a = 37500 km/h² (Answer)

part (b)

Now we can use the following equation to find deceleration

Where a is acceleration, s is distance travelled, v is final velocity and u is initial velocity

Given in the question

s = 44 m

changing to km

s = 0.044 km

v = 0 km/h (because it stops)

u = 100 km/h

2(a)(0.044) = (0)² – (100)²

0.088(a) = 0 - 10000

a = - 10000/0.088

a = - 113636.36 km/h2

The negative sign in the answer shows that it is deceleration

Therefore deceleration = 113636.36 km/h² (Answer)

6 0

3 years ago

Sam's job at the amusement park is to slow down and bring to a stop the boats in the log ride. you may want to review ( pages 29

meriva

The work should be at least equivalent to the kinetic energy possessed by the boat and its riders. The formula for kinetic energy is written below:

W = KE
W = 1/2*mv²
W = 1/2*(1,000 kg)(1.3 m/s)²
<em>W = 845 J</em>

7 0

3 years ago

Read 2 more answers

A 290-turn solenoid having a length of 32 cm and a diameter of 11 cm carries a current of 0.30 A. Calculate the magnitude of the

iris [78.8K]

The magnitude of the magnetic field inside the solenoid is 3.4×10^(-4) T.

To find the answer, we need to know about the magnetic field inside the solenoid.

<h3>What's the expression of magnetic field inside a solenoid?</h3>

Mathematically, the expression of magnetic field inside the solenoid= μ₀×n×I

n = no. of turns per unit length and I = current through the solenoid

<h3>What's is the magnetic field inside the solenoid here?</h3>

Here, n = 290/32cm or 290/0.32 = 906

I= 0.3 A

So, Magnetic field= 4π×10^(-7)×906×0.3 = 3.4×10^(-4) T.

Thus, we can conclude that the magnitude of the magnetic field inside the solenoid is 3.4×10^(-4) T.

Learn more about the magnetic field inside the solenoid here:

brainly.com/question/22814970

#SPJ4

6 0

1 year ago

How does the temperature of water change when it is heated on a stove top and then begins to boil?

guapka [62]

Answer:

Explanation:

First the water heats up to the boiling point ( temp increases)

then, as it boils it remains at constant temp ( boiling point)

5 0

2 years ago