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MaRussiya [10]
2 years ago
12

The ozone layer protects us from the harmful effects of which type of radiation?

Physics
1 answer:
leonid [27]2 years ago
3 0

Answer:

Hey there

The ozone layer or ozone shield is a region of Earth's stratosphere that absorbs most of the Sun's ultraviolet radiation

Can u have brainly

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A 24 volt battery is connected to a 3Ω resistor and a 5Ω resistor in series. What is the current in the circuit?
Vladimir [108]

Answer: 3 Amperes

Explanation:

Voltage of battery = 24 volts

R1 = 3Ω

R2 = 5Ω

Total resistance = ?

Current, I = ?

Since the resistors are connected in series, the total resistance (Rtotal) of the circuit is the sum of each resistance.

i.e Rtotal = R1 + R2

Rtotal = 3Ω + 5Ω = 8Ω

Now recall that voltage = current x resistance

i.e V = I x Rtotal

24volts = I x 8Ω

I = 24 volts / 8Ω

I = 3 amperes

Thus, there is 3 Amperes of current in the circuit

7 0
3 years ago
Lory of two metals, nickel and chromium, which are not too similar to each
bogdanovich [222]

Answer:

I don't understand your question

Explanation:

8 0
3 years ago
If you throw a ball at 35° and 10 m/s what is the horizontal component of velocity
wariber [46]

Answer:

8.2 m/s

Explanation:

The horizontal component of the velocity is given by:

v_x = v cos \theta

where

v = 10 m/s is the magnitude of the velocity

\theta=35^{\circ} is the angle at which the ball has been thrown, with respect to the horizontal

Substituting the values into the equation, we get

v_x=(10 m/s)(cos 35^{\circ})=8.2 m/s

3 0
3 years ago
The initial velocity of a car moving along a straight path was 0 meters/second. After 10 seconds, it reached a velocity of 25 me
maria [59]

Answer:

2.5m/s^{2}

Explanation:

We can use one of the kinematics equation to find the acceleration.

v = u + at

where v = final velocity, in m/s

u = initial velocity, in m/s

t = time in seconds

Given the information provided from the question,

v = 25m/s

u = 0m/s

t = 10s

Substitute these values into the kinematics equation.

25 = 0 + 10a

10a = 25

a = 25 / 10

= 2.5m/s^{2}

6 0
1 year ago
A 1000 kg automobile is traveling at an initial speed of 20 m/s. It is brought to a complete stop in 5 s over a distance of 50 m
ikadub [295]

Answer:

W = -2*10⁵ J

Explanation:

  • Assuming no friction present, we can find the work done by an external force stopping the car, applying the work-energy theorem.
  • This theorem says that the total work done on one object by an external net force, is equal to the change in the kinetic energy of the object.
  • If the automobile is brought to a complete stop, we can find the change of the kinetic energy as follows:

        \Delta K = K_{f} - K_{0}  = 0 - \frac{1}{2} * m* v_{0} ^{2}  \\\\  \Delta K = -\frac{1}{2}*1000kg*(20 m/s)^{2} = -200000 J= -2e5 J

  • So, the total work done in stopping the automobile, is -2*10⁵ J. The minus sign stems from the fact that the force and the displacement have opposite directions.
5 0
3 years ago
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