They’re right that is the answer
The velocity will remain unchanged (Newton’s 1st Law) unless a force acts on it. If no friction force, then the velocity remains constant.
May you attach your displacement vs. time graph picture and resend the question once again then I might be able to help you
Answer:
Orbital period of satellite is 5.83 x 10³ s
Explanation:
The orbital period of satellite revolving around Earth is given by the equation :
.....(1)
Here R is radius of Earth, h is height of satellite from the Earth's surface, M is mass of Earth and G is gravitational constant.
In this problem,
Height of satellite, h = 500 km = 500 x 10³ m
Substitute 6378.1 x 10³ m for R, 500 x 10³ m for h, 5.972 x 10²⁴ kg for M and 6.67 x 10⁻¹¹ m³ kg⁻¹ s⁻² for G in equation (1).
![T=\sqrt{\frac{4\pi ^{2} [(6378.1+500)\times10^{3} ]^{3} }{6.67\times10^{-11} \times5.972\times10^{24} } }](https://tex.z-dn.net/?f=T%3D%5Csqrt%7B%5Cfrac%7B4%5Cpi%20%5E%7B2%7D%20%5B%286378.1%2B500%29%5Ctimes10%5E%7B3%7D%20%5D%5E%7B3%7D%20%7D%7B6.67%5Ctimes10%5E%7B-11%7D%20%5Ctimes5.972%5Ctimes10%5E%7B24%7D%20%7D%20%7D)
<em>T</em> = 5.83 x 10³ s
Answer: of gamma rays with high energies.
Explanation:Gamma-ray bursts are extremely energetic explosions that have been observed in distant galaxies. They are the brightest electromagnetic events known to occur in the universe.
The frequency of the most energetic bursts has been measured at around 3.0×1021 3.0 × 10 21 Hz.