Question

a series circuit contains two devices one with a resistance of 10 ohms and one with a resistance of 4 ohms if the generator supplies a voteage of 42 v what is the magnitude of the current?

Answer 1

Current(I) = Voltage/Resistance

                = 42/(10+ 4)

                = 42/14  

Current = 3 A      

Answer 2

Answer:

i = 3 A

Explanation:

When two or more resistances are connected in series then the total effective resistance is given as

$R_{eq} = R_1 + R_2$

now we have

$R_{eq} = 10\: ohm + 4\: ohm$

$R_{eq} = 14\: ohm$

now from ohm's law we know that

$V = i R$

here we know that

V = 42 volts

R = 14 ohm

now from above equation

$42 = i \times 14$

$i = 3 A$