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boyakko [2]
3 years ago
7

Sanji has a square room with a perimeter of 42.5 feet. If she wants to hang a curtain along one full side of the room, how long

does the curtain need to be?
Mathematics
1 answer:
Alexeev081 [22]3 years ago
8 0

Answer:

The length of the curtain is 10.625 feet

Step-by-step explanation:

The length of the curtain to cover one side of the room depends on the shape of the room

Given a room shape of a square, we have;

Perimeter = 4 × Side length of the room

Length of the curtain = Side length of the room

Therefore;

Perimeter = 4 × Length of the curtain

42.5 feet = 4 × Length of the curtain

Length of the curtain = (42.5 feet)/4 = 10.625 feet

The length of the curtain = 10.625 feet.

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Artemon [7]

Answer:   1. ∠A= 80.75°  2. 41.79 cm^2

Step-by-step explanation:

Since, According to the sines low,

\frac{sin A}{CB} = \frac{sin C}{AB}

Here, CB= 4.1 cm,  AB = 3.3 and ∠ C = 52.6°

\frac{sin A}{4.1} = \frac{sin 52.6}{3.3}

⇒ sin A = 4.1\times\frac{sin 52.6}{3.3}

⇒  sin A =0.98699998308

⇒ A = 80.75°

2. Since, the area of the given figure = Area of the rectangle having dimension 8.3 × 4.2 + Area of the half square of radius 2.1

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3 years ago
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mrs_skeptik [129]
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Step-by-step explanation:

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A certain bookstore chain has two stores, one in San Francisco and one in Los Angeles. It stocks three kinds of books: hardcover
riadik2000 [5.3K]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

(a)

\left[\begin{array}{cccc}T&H&S&P\\S&600&1300&2000\\L&400&300&400\end{array}\right] = A.

In the above matrix A, the columns refers the three type of books and the rows refers the from which stores the books are been sold.

The numbers represents the corresponding sales in the month of January.

The sale is same for the 6 months.

Hence, 6A = \left[\begin{array}{cccc}T&H&S&P\\S&3600&7800&12000\\L&2400&1800&2400\end{array}\right]. This matrix 6A represents the total sales over the 6 months.

(b)

If we denote the books in stock at the starting of January by B, then

B = \left[\begin{array}{cccc}T&H&S&P\\S&1000&3000&6000\\L&1000&6000&3000\end{array}\right].

Each month, the chain restocked the stores from its warehouse by shipping 500 hardcover, 1,400 softcover, and 1,400 plastic books to San Francisco and 500 hardcover, 500 softcover, and 500 plastic books to Los Angeles.

If we represent the amount restocked books at the end of each month by another matrix C, then

C = \left[\begin{array}{cccc}T&H&S&P\\S&500&1400&1400\\L&500&500&500\end{array}\right].

This restocking will be done for 5 times before the end of June.

If there would be no sale, then the stock would be

B + 5C = \left[\begin{array}{cccc}T&H&S&P\\S&1000+2500&3000+7000&6000+7000\\L&1000+2500&6000+2500&3000+2500\end{array}\right] \\= \left[\begin{array}{cccc}T&H&S&P\\S&3500&10000&13000\\L&3500&8500&5500\end{array}\right].

Since, the total sale is given by 6A, at the end of June, the inventory in each store can be shown as following,

B+5C-6A \left[\begin{array}{cccc}T&H&S&P\\S&3500&10000&13000\\L&3500&8500&5500\end{array}\right] - \left[\begin{array}{cccc}T&H&S&P\\S&3600&7800&12000\\L&2400&1800&2400\end{array}\right] \\= \left[\begin{array}{cccc}T&H&S&P\\S&-100&2200&1000\\L&1100&6700&3100\end{array}\right]

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3 years ago
What is the product? 3x^5(2x^2+4+1)
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Answer:

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Step-by-step explanation:

3x^{5}(2x^{2} +4+1)

Multiply 3x^{5} by each term in the parentheses.

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Now, all you have to do is simplify.

6x^{7} +15x^{5}

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