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Klio2033 [76]
3 years ago
10

Which if the following steps were applied to ABCD to obtain A'B'C'D'

Mathematics
1 answer:
Zanzabum3 years ago
6 0

Answer:

First choice A because shifted 3 right and 1 down

Step-by-step explanation:

Please Brainlist

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Find the area of shaded region. Round to the nearest tenth.
Strike441 [17]

Answer: 108.35

Step-by-step explanation:

4 1
3 years ago
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Please help. Sooooo confused. GOAL is a quadrilateral in which GO is parallel to AL. If the measures of angle G=angle O = 40 deg
DanielleElmas [232]

Answer:

Angle A and L are 140 degrees each.

Step-by-step explanation:

Since GO and AL are parallel to each other, we can use the same side interior theorem to figure out angle A and L. Let's focus on GA first. We know that same side interior angles are supplementary (sum is 180 degrees). We know angle G is 40 degrees, so to figure out angle A, you do 180-40 which equals 140. So angle A is 140 degrees. You repeat this process for OL and you should also get 140 degrees for L.

3 0
3 years ago
A pump adds 5 gallons to a storage pond every 2 minutes. How many minutes will it take to pump 20 gallons into the pond?
Bumek [7]
8 min=20 gal
50min= 125gal

7 0
3 years ago
Find the function of which is the solution of 36y"-48y'-48y=0 with initial conditions y1(0)=1. y1'(0)=0
lilavasa [31]

Answer:

y=\frac{1}{4} e^{2x}+\frac{3}{4} e^{-\frac{2}{3}x }

Step-by-step explanation:

Let,  D=\frac{d}{dx}

Now, us simplify the given differential equation and write it in terms of D,

36y''-48y'-48y=0

or, 3y''-4y'-4y=0

or, (3D^2-4D-4)y=0

We have our auxiliary equation:

3D^2-4D-4=0

or, (3D+2)(D-2)=0

or, D=2, - \frac{2}{3}

Therefore our solution is,

y=Ae^{2x}+Be^{- \frac{2}{3}x}

and, y'=2Ae^{2x}-\frac{2}{3}Be^{\frac{2}{3}x }

Applying the boundary conditions, we get,

A+B=1

2A-\frac{2}{3}B=0

Solving them gives us,

A=\frac{1}{4} ,B=\frac{3}{4}

Hence,

y=\frac{1}{4} e^{2x}+\frac{3}{4} e^{-\frac{2}{3}x }

4 0
3 years ago
If the heights of 300 students are normally distributed with mean 68.0 inches and standard deviation 3.0 inches, how many studen
Lunna [17]
Given:
μ = 68 in, population mean
σ = 3 in, population standard deviation

Calculate z-scores for the following random variable and determine their probabilities from standard tables.

x = 72 in:
z = (x-μ)/σ = (72-68)/3 = 1.333
P(x) = 0.9088

x = 64 in:
z = (64 -38)/3 = -1.333
P(x) = 0.0912

x = 65 in
z = (65 - 68)/3 = -1
P(x) = 0.1587

x = 71:
z = (71-68)/3 = 1
P(x) = 0.8413

Part (a)
For x > 72 in, obtain
300 - 300*0.9088 = 27.36

Answer: 27

Part (b)
For x ≤ 64 in, obtain
300*0.0912 = 27.36

Answer: 27

Part (c)
For 65 ≤ x ≤ 71, obtain
300*(0.8413 - 0.1587) = 204.78

Answer: 204

Part (d)
For x = 68 in, obtain
z = 0
P(x) = 0.5
The number of students is
300*0.5 = 150

Answer: 150

3 0
3 years ago
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