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Over [174]
4 years ago
6

There is a simple pattern for determining if a binary number is odd. What is it and why does this pattern occur

Computers and Technology
2 answers:
kramer4 years ago
8 0
The rightmost digit is the one's digit ( 2^0 ). If it's set, the number is odd, else it's even.
andrew-mc [135]4 years ago
6 0

The answer to this question would be the least number (right most number). If the last digit of a binary number is 1, the number is odd; if it’s 0, the number is even.  If you add an even number with even number, the result should be even. But if there is just one odd number added, it will be odd. In binary, all the number is multiplied by 2x. It is pretty clear that all the number should be even beside the first/lowest multiplier   which has potential to be 1.  Everything about the binary number system is the same as the decimal number system with just one difference: the base is 2 instead of 10.

Further Explanation:-

Binary number system

Binary means base 2(note the prefix bi). Base 2 (binary) has 2 digits: 0, 1. since binary numbers are made up of binary digits, we often call a binary digit a bit (short for binary digit). We may also refer to a place value position as a bit. In other words, the binary number '1010' requires 4 bits to write, and those bits are '1', '0', '1' and '0'.For any number system that has a base b, the first b non-negative numbers are represented by the digits themselves. For base b=2 (binary), the first 2 numbers are 0 and 1.Counting in binary is just like counting in decimal, except that you run out of digits much more quickly and have to resort to more value places sooner. To count the number of eggs in a dozen in binary would be as follows: 0, 1, 10, 11, 100, 101, 110, 111, 1000, 1001, 1010, 1011, 1100.  

Example:  

1101 represents an odd number (13); 10010 represents an even number (18).  To convert a binary number to base 2k , split it into groups of k digits (adding leading 0s if necessary), then convert each group to base 2k . Ex: Convert the number 1001011111 to base 8. First, note that 8 = 23 , so we should split the number into groups of 3 digits: 001 001 011 111 Note that we added two leading 0s to make the number of digits a multiple of 3. Next, we convert each group of 3 digits to base 8: 001 001 011 111 1 1 3 7 Thus, the number in base 8 is 1137.

Learn more:

  • What is the binary answer to the binary number 100 added to the binary number 11?

         brainly.com/question/6561005

Keywords:  binary, number system, decimal, conversion, even binary number, odd binary.

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QUESTION 6 Which of the following is a class A IPv4 address? a. 118.20.210.254 b. 183.16.17.30 c. 215.16.17.30 d. 255.255.0.0
shepuryov [24]

Answer:

a. 118.20.210.254

Explanation:

Here are the few characteristics of Class A:

First bit of the first octet of class A is 0.

This class has 8 bits for network and 24 bits for hosts.

The default sub-net mask for class A IP address is 255.0.0.0

Lets see if the first bit of first octet of 118.20.210.254 address is 0.

118 in binary (8 bits) can be represented as : 1110110

To complete 8 bits add a 0 to the left.

01110110

First bit of the first octet of class A is 0 So this is class A address.

For option b the first octet is : 183 in the form of bits = 10110111 So it is not class A address

For option c the first octet is 215 in the form of bits = 11010111 So it is not class A address

For option d the first octet is 255 in the form of bits = 11111111. The first bit of first octet is not 0 so it is also not class A address.

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An important part of the development of transport is safety. how can you, when you get around in different ways, contribute to m
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Answer:

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Answer:

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Explanation:

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