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3 years ago

There is a simple pattern for determining if a binary number is odd. What is it and why does this pattern occur

Computers and Technology

2 answers:

kramer3 years ago

8 0

The rightmost digit is the one's digit ( 2^0 ). If it's set, the number is odd, else it's even.

andrew-mc [135]3 years ago

6 0

The answer to this question would be the least number (right most number). If the last digit of a binary number is 1, the number is odd; if it’s 0, the number is even. If you add an even number with even number, the result should be even. But if there is just one odd number added, it will be odd. In binary, all the number is multiplied by 2x. It is pretty clear that all the number should be even beside the first/lowest multiplier which has potential to be 1. Everything about the binary number system is the same as the decimal number system with just one difference: the base is 2 instead of 10.

Further Explanation:-

Binary number system

Binary means base 2(note the prefix bi). Base 2 (binary) has 2 digits: 0, 1. since binary numbers are made up of binary digits, we often call a binary digit a bit (short for binary digit). We may also refer to a place value position as a bit. In other words, the binary number '1010' requires 4 bits to write, and those bits are '1', '0', '1' and '0'.For any number system that has a base b, the first b non-negative numbers are represented by the digits themselves. For base b=2 (binary), the first 2 numbers are 0 and 1.Counting in binary is just like counting in decimal, except that you run out of digits much more quickly and have to resort to more value places sooner. To count the number of eggs in a dozen in binary would be as follows: 0, 1, 10, 11, 100, 101, 110, 111, 1000, 1001, 1010, 1011, 1100.

Example:

1101 represents an odd number (13); 10010 represents an even number (18). To convert a binary number to base 2k , split it into groups of k digits (adding leading 0s if necessary), then convert each group to base 2k . Ex: Convert the number 1001011111 to base 8. First, note that 8 = 23 , so we should split the number into groups of 3 digits: 001 001 011 111 Note that we added two leading 0s to make the number of digits a multiple of 3. Next, we convert each group of 3 digits to base 8: 001 001 011 111 1 1 3 7 Thus, the number in base 8 is 1137.

Learn more:

What is the binary answer to the binary number 100 added to the binary number 11?

brainly.com/question/6561005

Keywords: binary, number system, decimal, conversion, even binary number, odd binary.

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3 years ago

Write a program that reads a list of integers, and outputs the two smallest integers in the list, in ascending order. The input

kompoz [17]

Answer:

Following are the program in the C++ programming Language.

//header files

#include <iostream>

#include <vector>

using namespace std;//name space

// define main method

int main()

{

//set integer variables

int size, num;

//get input the size of the list

cout<<"Enter size of list: ";

cin >> size;

//set integer type vector variable

vector<int> vecs;

//Set the for loop

for (int index = 0; index < size; ++index)

{//get elements of the list from the user

cout<<" :";

cin >> num;

//push back the elements of the list

vecs.push_back(num);

}

//storing the first two elements in variable

int n = vecs[0], n1 = vecs[1], current , temp;

//set if conditional statement

if (n > n1)

{

//perform swapping

temp = n;

n = n1;

n1 = temp;

}

//Set for loop

for (int index = 2; index < size; ++index)

{

//store the value of the vector in the variable

current = vecs[index];

//set if conditional statement

if (current < n)

{

//interchange the elements of the variable

n1 = n;

n = current;

}

else if(current < n1)

{

n1 = current;

}

//print the value of first two smallest number.

cout <<"\n" <<n << " " << n1 << endl;

return 0;

}

<u>Output:</u>

Enter size of list: 5

:10

:21

2 3

Explanation:

Here, we define the required header files and namespace then, we define "main()" function inside the main function.

Set two integer data type variable "size", "num".
Print message and get input from the user in variable "size".
Then, we set integer vector type variable "vecs".
Set the for loop to get the number of input in the variable "num" from user.
Then, we push back the elements of the list and store first two elements of the list in the variable "n", "n1".
Set the conditional statement to perform swapping.

Define the for loop to store the list of the vector in the integer type variable "current".
Finally, we print the value of the two smallest numbers of the list.

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