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SSSSS [86.1K]
3 years ago
13

Solve for x What kind of angle And substitute it back in

Mathematics
2 answers:
Debora [2.8K]3 years ago
8 0
So the angles in this are alternate interior angles. All alternate interior angle are congruent, so to find x, you make the equation equal 85. So it would be 14x+1=85. Next you isolate the variable by subtracting the 1 to the other side then dividing the entire expression by 14. In the end you should find that x=6. I assume that substituting it back in is substituting the x back into the expression. So just replace x with 6. 14(6)+1=85; 84+1=85; 85=85.

The answer is x=6, they are alternate interior angles, and substituting the new x into the expression should result in 14(6)+1=85; 84+1=85; 85=85.

Hope this helps, good luck! :)
Olenka [21]3 years ago
3 0
Congruent angle or alternate interior angles

X=6

The angle is 85 degrees
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80 square yards

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so you have to divide 20 into 100 to see how much each sheep gets. Each sheep gets 5 square yards. Then you just multiply how much each sheep gets by 5 and get 80 square yards.

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An urn contains two black balls and three red balls. If two different balls are successively removed, what is the probability th
lidiya [134]

You can extract two balls of the same colour in two different way: either you pick two black balls or two red balls. Let's write the probabilities of each pick in each case.

Case 1: two black balls

The probability of picking the first black ball is 2/5, because there are two black balls, and 5 balls in total in the urn.

The probability of picking the second black ball is 1/4, because there is one black ball remaining in the urn, and 4 balls in total (we just picked the other black one!)

So, the probability of picking two black balls is

P(\text{two blacks}) = \dfrac{2}{5} \cdot \dfrac{1}{4} = \dfrac{2}{20} = \dfrac{1}{10}

Case 2: two red balls

The probability of picking the first black ball is 3/5, because there are three red balls, and 5 balls in total in the urn.

The probability of picking the second red ball is 2/4=1/2, because there are two red balls remaining in the urn, and 4 balls in total (we just picked the other red one!)

So, the probability of picking two red balls is

P(\text{two reds}) = \dfrac{3}{5} \cdot \dfrac{1}{2} = \dfrac{3}{10}

Finally, the probability of picking two balls of the same colour is

P(\text{same colour}) = P(\text{two blacks})+ P(\text{two reds}) = \dfrac{1}{10} + \dfrac{3}{10} = \dfrac{4}{10} = \dfrac{2}{5}

7 0
2 years ago
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