The answer to your question is 11/12
<span>difference of squares formula:
</span>a^2<span> – b^</span>2<span> = (a + b)(a – b)
</span>so answers are
<span>(3 + xz)(–3 + xz)
</span><span>(y2 – xy)(y2 + xy)
</span><span>(64y2 + x2)(–x2 + 64y2)
</span><span>
cause
</span><span>(3 + xz)(–3 + xz)
= </span><span>(xz + 3 )(xz - 3)
= x^2z^2 - 9
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</span>(y^2 – xy)(y^2 + xy)
= y^4 -x^2y^2
----------
<span>(64y^2 + x^2)(–x2 + 64y^2)
=</span>(64y^2 + x2)(64 - x^2)<span>
= 64^2 y^4 - x^4</span>
Answer:
Step-by-step explanation:
"Two times one number added to three times a second number is 21.
2x + 3y = 21
"The second number is ten less than five times the first number"
y = 5x-10
Substitution
2x+3(5x-10) = 21
2x + 15x - 30 = 21
17x = 51
x = 3
y = 5x-10 = 5
Answer:
Option D. 5
Step-by-step explanation:
we know that
The initial value of the function is the y-intercept, so is the value of the function when the value of x is equal to zero
In this problem observing the table
For x=0
The value of y is equal to y=5
therefore
The initial value is 5
